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First find out how many grams in 1 mole:
Nitrogen is 14.007 g/mol, Hydrogen is 1.0079 g/mol, and Chlorine is 35.453 g/mol
There are 4 Hydrogen, so 14.007 + 4*(1.0079) + 35.453 = 53.4916 g/mol
(50 g)/(53.4916 g/mol) = 0.9347 moles
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∙ 13y ago
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∙ 9y ago0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
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∙ 9y agoIn organic chemistry, 0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
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∙ 8y agoThe solubility of ammonium chloride in water at 70 oC is 602 g/L.
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∙ 8y agoThe solubility of ammonium chloride at 50 oC in water is 50,4 g/100 g.
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∙ 8y agoThe answer depends on the pressure. At 1 atmosphere, it is 50.4 grams.
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∙ 6y ago115 mL of 2,50 M NH4Cl solution contain 15,38 g salt.
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How many moles of excess sulfuric acid are left over after the reaction is complete 2 nh3 aq plus h2so4 aq nh4 2so4 aq?
You gave no starting moles/mass.
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
How many moles are there in 4.69 g of (NH4)2SO4?
Molar mass of (NH4)2SO4 is 132.14 g/mol, so4.69 (g) / 132.14 (g/mol) = 0.0355 mol
What is the abbreviation for ammonium sulfate?
(nh4)2so4
How many moles of (NH4)2SO4 do you have?
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
How many grams of sulfuric acid are needed to react with 8 mol of ammonium hydroxide?
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
What is the molar mass of (NH3)2SO4 in grams?
Maybe you meant (NH4)2SO4 because not sure (NH3)2SO4 exists, but the answer to the question as written would be:(NH3)2SO4 has 2N, 6H, 1S and 4O2N = 2x14.0 = 28.06H = 6x1.0 = 6.01S = 1x32.1 = 32.14O = 4x16.0 = 64.0Add them up to get 130.1 g/mole
How many moles of ammonium sulfate can be made from the reaction of 30.0 mol of NH3 with H2So4 according to the following equation 2 NH3 H2So - (NH4)2So4?
There are 15 moles of ammonia sulfate in the reaction of 30.0 mol of NH3. This goes from the formula 2 NH3 H2so take away (NH4)2So4.
How many grams of oxygen are in 1.851023 formula units of (NH4)2SO4?
This mass is 244,459.10e23 g.
How many moles of excess sulfuric acid are left over after the reaction is complete 2 nh3 aq plus h2so4 aq nh4 2so4 aq?
You gave no starting moles/mass.
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
What is (NH4)2SO4?
It is not complete...ammonium sulfate is (NH4)2SO4
How many moles are there in 4.69 g of (NH4)2SO4?
Molar mass of (NH4)2SO4 is 132.14 g/mol, so4.69 (g) / 132.14 (g/mol) = 0.0355 mol
The formula for ammonium sulfate is?
Ammonium sulfate is (NH4)2SO4
What is the name of the compound (NH4)2SO4?
Ammonium sulfate, (NH4)2SO4(s) and sodium hydroxide
