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To determine the number of moles in 50 grams of (NH4)2SO4, we first need to calculate the molar mass of the compound. The molar mass of (NH4)2SO4 is 132.14 g/mol. Next, we use the formula: moles = mass/molar mass. Therefore, moles = 50g / 132.14 g/mol ≈ 0.378 moles of (NH4)2SO4.
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How many moles are there in 4.69 g of (NH4)2SO4?
To find the number of moles in 4.69 g of (NH4)2SO4, you need to first calculate the molar mass of (NH4)2SO4. The molar mass of (NH4)2SO4 is 132.14 g/mol. Then, you can use the formula: moles = mass / molar mass. Therefore, moles = 4.69 g / 132.14 g/mol ≈ 0.035 moles of (NH4)2SO4.
What is the symbol ammonium sulphate?
The chemical symbol for ammonium sulfate is (NH4)2SO4. It is a commonly used inorganic salt compound.
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
400.0 grams of ammonia react with 56.0 moles of sulfuric acid to produce ammonium sulfate?
The reaction between 400.0 grams of ammonia and 56.0 moles of sulfuric acid will produce ammonium sulfate. To calculate the amount of product formed, you would need to determine the limiting reactant, which in this case would be sulfuric acid as it is in lower amount compared to ammonia. The balanced chemical equation for the reaction would be 2NH3 + H2SO4 → (NH4)2SO4.
How many moles of (NH4)2SO4 do you have?
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
How many moles are there in 4.69 g of (NH4)2SO4?
To find the number of moles in 4.69 g of (NH4)2SO4, you need to first calculate the molar mass of (NH4)2SO4. The molar mass of (NH4)2SO4 is 132.14 g/mol. Then, you can use the formula: moles = mass / molar mass. Therefore, moles = 4.69 g / 132.14 g/mol ≈ 0.035 moles of (NH4)2SO4.
What is the symbol ammonium sulphate?
The chemical symbol for ammonium sulfate is (NH4)2SO4. It is a commonly used inorganic salt compound.
What is the molar mass of (NH3)2SO4 in grams?
Maybe you meant (NH4)2SO4 because not sure (NH3)2SO4 exists, but the answer to the question as written would be:(NH3)2SO4 has 2N, 6H, 1S and 4O2N = 2x14.0 = 28.06H = 6x1.0 = 6.01S = 1x32.1 = 32.14O = 4x16.0 = 64.0Add them up to get 130.1 g/mole
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
How many moles of ammonium sulfate can be made from the reaction of 30.0 mol of NH3 with H2So4 according to the following equation 2 NH3 H2So - (NH4)2So4?
There are 15 moles of ammonia sulfate in the reaction of 30.0 mol of NH3. This goes from the formula 2 NH3 H2so take away (NH4)2So4.
How many grams of oxygen are in 1.851023 formula units of (NH4)2SO4?
This mass is 244,459.10e23 g.
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
400.0 grams of ammonia react with 56.0 moles of sulfuric acid to produce ammonium sulfate?
The reaction between 400.0 grams of ammonia and 56.0 moles of sulfuric acid will produce ammonium sulfate. To calculate the amount of product formed, you would need to determine the limiting reactant, which in this case would be sulfuric acid as it is in lower amount compared to ammonia. The balanced chemical equation for the reaction would be 2NH3 + H2SO4 → (NH4)2SO4.
How many grams of sulfuric acid are needed to react with 8 mol of ammonium hydroxide?
The balanced chemical equation for the reaction is 1 mol of sulfuric acid reacts with 2 mol of ammonium hydroxide. Therefore, for 8 mol of ammonium hydroxide, 4 mol of sulfuric acid are needed. To calculate the grams of sulfuric acid needed, you would multiply the number of moles by the molar mass of sulfuric acid.
How many moles of ammonium sulfate are in 150g sample?
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
