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5.88 mg ClF3 (1 gram/1000 mg)(1 mole ClF3/92.45 g)(3 mole F/1 mole ClF3)(6.022 X 10^23/1 mole F)

= 1.15 X 10^20 atoms of fluorine

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12y ago
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Q: How many atoms of F are in 5.88 mg of ClF3?
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