The ionic compound Al2O2 forms when aluminum reacts with oxygen.
he following equation is balanced 4Al 3O2 -- 2Al2O3 is not a balanced equation.on the reactants side we haev 4 atoms of Al and we have 24 atoms of oxygen. but on products side we have 24Al but 6 atoms of oxygen.this violates conservation of mass.
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
The formula would be AlCl3, which is aluminum chloride.
four atoms in AlBr3
4
6
The 2 in front means 2 formula units, or 2 moles of the compound Al3O2. So you would multiply the 2 in front times the subscripts in the formula unit Al3O2. In the formula unit Al3O2, there are 5 atoms. Multiply that by the 2 in front and you get 10 atoms.
It's Aluminum Oxide.
2Al2O3 --> 4Al + 3O2
The ionic compound Al2O2 forms when aluminum reacts with oxygen.
4Al + 3O2 -> 2Al2O3
he following equation is balanced 4Al 3O2 -- 2Al2O3 is not a balanced equation.on the reactants side we haev 4 atoms of Al and we have 24 atoms of oxygen. but on products side we have 24Al but 6 atoms of oxygen.this violates conservation of mass.
4Al+3O2-->2Al2O3
It means that there are two molecules of Aluminum Oxide, Al2O3.
2Al2O3 + 3C -> 3CO2 + 4Al
No. If you mean 4Al3O2. And If you mean 4Al + 3O2 ------> AL2O, it is still not balance.