Since a single atom is the formula unit for carbon, 1 mole of it contains Avodagro's number of atoms, about 6.022 X 1023.
6.02214179 x 1023 atoms - Avogadro's number.
only one if its C, if its one mole of C2 then there is two atoms of carbon
One mole of carbon has 12,01 g.
1 mole contain 6,022 140 857(74).10e23 atoms, ions or molecules; this is the Avogadro number.
6.023*10^23 *12
avogadro numbers of atoms
12
Assuming you are talking about a period made by carbon atoms (Pencil lead is almost pure carbon) and that period has a mass of 0.0001g Then the answer is 5x1018 atoms.There are 12.011g of carbon per mol, there are 6.022x1023 atoms per mol.1mol | 6.022x1023 atoms | 0.001 g |-----------|--------------------------|-------------| = 5x1018 atoms/period12.011g | 1 mol | period |
Number of particles = number of mol x avogadro constant = 1 x 6.02 x 1023
3.90x10^24 atoms To arrive at an answer in units of carbon atoms, first we must cancel out the grams by diving 84.3g C2H2 by the molar mass of C2H2 (26.038g/mol). This molar mass is calculated by adding the masses of 2 carbon atoms (12.011g/mol) and 2 hydrogen atoms (1.008g/mol). This renders units of moles of ethyne. Next multiply by Avagadro's number (6.022x10^23 atoms/mol) to cancel the moles of ethyne and reach atoms of ethyne. Finally, because there are 2 carbon atoms in C2H2, multiply by 2 atoms Carbon/1 atom C2H2 to reach the final answer of 3.90x10^24 atoms of Carbon. This answer has been rounded to three significant figures because the lowest known value of significant figures throughout the calculations was three (84.3). The entire process is as follows: 84.3g C2H2 x (1 mol C2H2)/(26.038 g C2H2) x (6.022x10^23 atoms C2H2)/(1 mol C2H2) x (1 atoms C2H2)/(2 atom C) = 3.90x10^24 atoms C
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6
Assuming you are talking about a period made by carbon atoms (Pencil lead is almost pure carbon) and that period has a mass of 0.0001g Then the answer is 5x1018 atoms.There are 12.011g of carbon per mol, there are 6.022x1023 atoms per mol.1mol | 6.022x1023 atoms | 0.001 g |-----------|--------------------------|-------------| = 5x1018 atoms/period12.011g | 1 mol | period |
The questions asks how many moles of carbon atoms.Molar mass is defined as the mass of one mole of a substance or in this case 6.022x1023 atoms of carbon. So the molar mass for carbon is 12.0 g/mol. Therefore the number of moles of carbon atoms is just 36/12.0 = 3.0 moles of carbon.How many atoms are in 36 grams of Carbon?[36 (gC) /12.0 (gC/molC)] * 6.02*10+23 (atoms C/molC) = 1.8*10+24 atoms in 36 g Carbon
Glucose is 180.16 g/mol. Doing stoichiometry, this means 1.97 grams is 0.0109 mol glucose. Because there are 6 mols of carbon per 1 mol of glucose, that means there are 0.0656 mols of carbon in this sample. One mole is equivalent to 6.023 x 1023 atoms, which leads to 3.95 x 1022 carbon atoms.
Number of particles = number of mol x avogadro constant = 1 x 6.02 x 1023
3.90x10^24 atoms To arrive at an answer in units of carbon atoms, first we must cancel out the grams by diving 84.3g C2H2 by the molar mass of C2H2 (26.038g/mol). This molar mass is calculated by adding the masses of 2 carbon atoms (12.011g/mol) and 2 hydrogen atoms (1.008g/mol). This renders units of moles of ethyne. Next multiply by Avagadro's number (6.022x10^23 atoms/mol) to cancel the moles of ethyne and reach atoms of ethyne. Finally, because there are 2 carbon atoms in C2H2, multiply by 2 atoms Carbon/1 atom C2H2 to reach the final answer of 3.90x10^24 atoms of Carbon. This answer has been rounded to three significant figures because the lowest known value of significant figures throughout the calculations was three (84.3). The entire process is as follows: 84.3g C2H2 x (1 mol C2H2)/(26.038 g C2H2) x (6.022x10^23 atoms C2H2)/(1 mol C2H2) x (1 atoms C2H2)/(2 atom C) = 3.90x10^24 atoms C
1 mol Cu Atoms (6.02x10^23 atoms)
One mole of any element contains 6.02 x 1023 atoms. So 1mole of carbon = 6.02x1023 atoms. 0.8mole of carbon = 0.8 x 6.02x1023 0.8 mole of carbon = 4.816 x 1023
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
1-butene has four carbon atoms.
The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6
3.011 x 1023 atoms of carbon will weigh about 6 grams One mole of carbon atoms weighs 12.011 grams, and there are 6.022 x 1023 atoms in a moles. So you have half as many atoms, so the mass would be half as much or 6.0055 grams to be precise.
1 mol of He contains apx 6.02214x10^23 atoms