How many atoms of gallium are in 2.85 x 103 g of gallium?
The formula to find number of atoms is
Mol = No. of atoms is divided by NA
When NA=6.02x1023
So, 2.3 × (6.02 × 1023)= 1.38 × 1024
91.93548387 atoms
1.004 moles Bi x 6.02x10^23 atoms/mole = 6.04x10^23 atoms of bismuth
The answer is 2,1077494515.10e+23 atoms.
3,00 moles of Li have 18,066422571.10e23 atoms.
2.80x10^24 atoms x 1 mol/6.02x10^23 atoms = 4.65 moles
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
1.004 moles Bi x 6.02x10^23 atoms/mole = 6.04x10^23 atoms of bismuth
The answer is 2,1077494515.10e+23 atoms.
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
3,00 moles of Li have 18,066422571.10e23 atoms.
2.80x10^24 atoms x 1 mol/6.02x10^23 atoms = 4.65 moles
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
The answer is 7,829.10 ex.23 atoms.
Approx 7.925*10^23 atoms.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
Divide that number of atoms by 6.02x10^23 atoms/mole
There are 9.33 moles of carbon in 5.62 atoms of carbon.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li