2Ca: 2, C: 1, O3: 3, 2 + 1 + 3 = 6
In this reaction, calcium is being oxidised. In 2Ca, its oxidaton state is 0 and after the reaction it is increased to +2 which forms a bong with oxygen ion. Since its oxidation state is increased from 0 to +2, it is being oxidised. Or you can look at it in another different manner. Calcium gains oxygen in the reaction thus it is being oxidised. It also loses electrons to form an ion which reacts with oxygen ion. Any substance is being oxidised when it oxidation state increases, gains oxygen atoms, loses hydrogen atoms or loses electrons.
.183mol CaO Ca is your limiting reactant, O2 is your excess reactant. thus 7.34g Ca = .183mol Ca, since the balanced reaction is 2Ca + 1 O2 -> 2 CaO, 1 mol Ca = 1 mol Cao and .183mol CaO is produced.
2Ca + O2 = 2 CaO
2Ca + O2 ------> 2CaO
2Ca: 2, C: 1, O3: 3, 2 + 1 + 3 = 6
In this reaction, calcium is being oxidised. In 2Ca, its oxidaton state is 0 and after the reaction it is increased to +2 which forms a bong with oxygen ion. Since its oxidation state is increased from 0 to +2, it is being oxidised. Or you can look at it in another different manner. Calcium gains oxygen in the reaction thus it is being oxidised. It also loses electrons to form an ion which reacts with oxygen ion. Any substance is being oxidised when it oxidation state increases, gains oxygen atoms, loses hydrogen atoms or loses electrons.
2Ca+O2---->2CaO
2Ca(s) + O2(g) ----> 2CaO(s)
Calcium hydroxide = Ca(OH)2 Ca = 1 atom OH = 2 atoms
3ac + 2ca = 3ac + 2ac = (3 + 2)(ac) = 5ac
.183mol CaO Ca is your limiting reactant, O2 is your excess reactant. thus 7.34g Ca = .183mol Ca, since the balanced reaction is 2Ca + 1 O2 -> 2 CaO, 1 mol Ca = 1 mol Cao and .183mol CaO is produced.
Ca(ClO3)2 --> CaCl2 + 3O2 is the equation for calcium chlorate to calcium chloride + oxygen gas.
Calcium most likely will react with the oxygen in the air. 2Ca(s) + O2(g) -->2CaO(s). It would form solid calcium oxide.
2Ca + O2 ------> 2CaO
2Ca + O2 = 2 CaO
Formula: (CH3COO)2Ca