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How many moles of the product form when 0.016 mol of O2 completely reacts 2Ca plus O2 ----- 2CaO?
Wiki User
∙ 11y ago
.183mol CaO
Ca is your limiting reactant, O2 is your excess reactant.
thus 7.34g Ca = .183mol Ca, since the balanced reaction is 2Ca + 1 O2 -> 2 CaO, 1 mol Ca = 1 mol Cao and .183mol CaO is produced.
Wiki User
∙ 14y ago
Wiki User
∙ 13y ago4.25 mole CaCO3 (3 mole O/1 mole CaCO3)(6.022 X 10^23/ 1 mole O)(1 mole O atoms/6.022 X 10^23)
= 12.8 moles of oxygen atoms
Wiki User
∙ 11y ago2Ca + O2 --> 2CaO
0.016 moles O2 (2 mole CaO/1 mole O2)
= 0.032 moles calcium oxide produced
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