8*sizeof (void *)
common values are: 16, 32, 64
Suppose that we're talking about C on an x86 32-bit processor it should be 4-bytes (32-bits). Since the pointer has to be able to hold any memory location it should be the same number of bits as the processor.
The answer will depend on how many numbers there are, how wide the sectors are, whether or not the pointer spins freely and is spun fairly. Since you have not bothered to share any of those crucial bits of information, I cannot provide a more useful answer.The answer will depend on how many numbers there are, how wide the sectors are, whether or not the pointer spins freely and is spun fairly. Since you have not bothered to share any of those crucial bits of information, I cannot provide a more useful answer.The answer will depend on how many numbers there are, how wide the sectors are, whether or not the pointer spins freely and is spun fairly. Since you have not bothered to share any of those crucial bits of information, I cannot provide a more useful answer.The answer will depend on how many numbers there are, how wide the sectors are, whether or not the pointer spins freely and is spun fairly. Since you have not bothered to share any of those crucial bits of information, I cannot provide a more useful answer.
12 bits
The stack pointer is 16 bits in size on the 8085 because that is how Intel designed it. The address bus is also 16 bits, so it made sense for the program and stack to be located anywhere in that address space.
In 32 bit address space it will most likely be 4 bytes, since 8 bits is a byte and 32 bits / 8 bits = 4. In 64 bit address space it should be 8 bytes (64 bits / 8 bits = 8). It is architecture dependent so use the sizeof() function.
64 bits
Totals bits for IPv6 = 128
32
12 Bits
32
A pointer, used in business or teaching = מַצבִּיעַ (matzbia)the specialty pointer used to read the torah = יד (yad)
The pointer that is used when reading the Torah is called a yad