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The answer is largely O/S and architecture specific, though 4KB and 8KB pages sizes are probably the most common.
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∙ 14y ago
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Why are page files used?
On a 32-bit system it is only possible to address a maximum of 2^32 bytes of memory (4,294,967,296 bytes which is 4 gigabytes). Memory is allocated in contiguous blocks such that if your program requires x bytes of memory, a block of x contiguous bytes must be available to meet the allocation request. If there is no single block large enough to meet the required allocation, you will get an out of memory error, even if there's more than x bytes of physical memory available in total. To avoid these problems, we use virtual memory. If there is no single block available to meet an allocation, existing allocations can be temporarily moved to a page file, thus freeing up the physical memory. When memory that has been paged out is required, other allocations can be paged out to allow the required memory to be paged in. Given that the contents of memory are swapped to and from the page file, the page file is often called a swap file. Data that was paged out of one physical address may be paged in to a completely different physical address. However, the virtual address does not change; the memory manager performs the translation between the physical and virtual addresses. This makes it possible for a 32-bit system to operate with a full complement of 4 gigabytes of memory even when the system has less than 4 gigabytes of physical memory installed. 64-bit systems allow us to address 18,446,744,073,709,551,616 bytes of memory which is far more memory than physically exists on the planet! For practical reasons, we can only use a small fraction of the full address space, however page files and virtual memory make it possible to use far more addresses than might be physically available.
How many pages is 108 KB?
It depends what amount of content the page has. If the page is empty with almost no words it will be a little amount of bytes. If the page has soo much content then it will have more bytes. But to answer your question ill say " It Depends "
How many bytes for a page of words?
A cell phone text message is 140 or 160 bytes based on service provider. As for a text page. A single letter is 1 byte. So it depends on paper size etc.
What efficiency Computer based information systems can add to the ordinary information systems?
The process includes 198656 bytes,how many frames needed if each size of the page is included 4096 bytes?
How would you obtain a far address from segment and offset address of a memory location?
Pointers to far objects are stored using four bytes (32 bits). The bytes are stored little endian or low to high order. The first word contains the 14-bit memory offset (bits 14 and 15 are always 0). The second word contains the page number (or segment number for function pointers). The memory address is calculated as follows: Variable Address = (Page * 0x4000L) + OffsetFunction Address = (Segment * 0x10000L) + Offset
Where in windows does it show how many mega bytes are in the file or page you are looking at?
Right click on the file and select properties. The size is listed there.
Consider a logical address space of eight pages of 1024words each mapped onto a physical memory of 32 frames how many bits are there in the logical address?
As was given for a 4 Page, 1024 words & 64 frames (shown below) 4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2+10=12 bits Physical memory = 10 +6 =16 bits The answer for this problem is 13. 8 pages -> 2^3 bits 1024 bytes -> 2^10 bits 32 frames -> 2^5 bits Therefore: Logical memory = 3+10=13 bits (Page + Word) Physical memory = 10 + 5 =15 bits (Word + Frame)
What is dirty page in virtual memory management?
it's the page that has been modified in main memory(physical memory), but not yet rewritten in the disk.
Memory is allocated in 4k segments called what?
Memory page.
Interleaving memory is best described as?
A page-division of memory.
When does page fault occur?
A page fault occurs when a program accesses a memory page that is not currently in physical memory (RAM). This triggers the operating system to fetch the required page from secondary memory (disk) into RAM, allowing the program to continue execution.
What is Google's home page size?
5200 bytes. Downloads mighty quickly, doesn't it?
