The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To determine the number of molecules in 60 g of ethane, you need to first calculate the number of moles of ethane using its molar mass (30 g/mol). Then, you can convert moles to molecules using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
The covalent name of C2H6 is ethane.
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
For the complete combustion of ethane (C2H6), each molecule of ethane reacts with 3.5 molecules of oxygen (O2). At standard conditions, 22.4 liters of any gas corresponds to 1 mole. Therefore, you would need 3.5 moles of oxygen to burn 1 mole of ethane at standard conditions.
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
124 grams of ethane is equal to 4,124 moles.
To determine the number of molecules in 60 g of ethane, you need to first calculate the number of moles of ethane using its molar mass (30 g/mol). Then, you can convert moles to molecules using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
1. Given: mass = 0.334g of C2H6, CAtomicWeight = 12.01, HAtomicWeight = 1.008 Required: a. Molar Mass of Ethane b. Number of molecules of C2H6 in 0.334g of C2H6 Formula: a. (n = (2 x CAtomicWeight) + (6 x HAtomicWeight) b. mass x (1 mole / a ) x (6.022x1023 molecules / 1 mole) Solution: a. Molar Mass of Ethane n = (2 x 12.01) + (6 x 1.008) n = 24.02 + 6.0498 n = 30.0698 b. Number of molecules n = 0.334 x (1 mole / 30.0698 g) x (6.022x1023 molecules / 1 mole) n = 6.689x1021 molecules FINAL Answer: The are 6.689x1021 molecules in 0.334g of Ethane
7/2O2+C2H6->2CO2+3H2O Mole ratio of C2H6:CO2=1:2 No.of mole of CO2=2mol
at STP 1 mole occupies 22.4 litres. 64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules
The covalent name of C2H6 is ethane.
Ethane is C2H6.
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.
To find the number of hydrogen atoms in 90 amu of ethane (C2H6), use the molar mass of ethane to determine the number of moles present. Next, use the molecular formula of ethane to calculate the number of hydrogen atoms in one mole, and then multiply by the number of moles present to find the total number of hydrogen atoms.
For the complete combustion of ethane (C2H6), each molecule of ethane reacts with 3.5 molecules of oxygen (O2). At standard conditions, 22.4 liters of any gas corresponds to 1 mole. Therefore, you would need 3.5 moles of oxygen to burn 1 mole of ethane at standard conditions.