0
What else can I help you with?
How many carbon atoms are contained in 5.50 gms of ethane?
30 g of ethane will have 6.023 x 1023 molecules of ethane So, 5.5 g will have 1.104 x 1023 molecules of ethane Since there are two carbon atoms, in one molecule of ethane, 5.5 g of ethane will have 2.208 x 1023 atoms of carbon.
How many molecules of ethane gas C2H6 are in 15 grams of the compound?
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many molecules are there in 60 g of acetic acid C2H4O2?
The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.
What is the specific enthalpy of combustion of ethane?
The specific enthalpy of combustion of ethane is approximately -1560 kJ/mol.
What is the mass of ethane gas inside a 5.00 L vessel at STP?
The molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L. Ethane gas has a molar mass of 30.07 g/mol. Therefore, the mass of ethane gas in a 5.00 L vessel at STP can be calculated as (5.00 L / 22.4 L) * 30.07 g/mol.
How many carbon atoms are contained in 5.50 gms of ethane?
30 g of ethane will have 6.023 x 1023 molecules of ethane So, 5.5 g will have 1.104 x 1023 molecules of ethane Since there are two carbon atoms, in one molecule of ethane, 5.5 g of ethane will have 2.208 x 1023 atoms of carbon.
How many molecules of ethane gas C2H6 are in 15 grams of the compound?
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many molecules are there in 60 g of acetic acid C2H4O2?
The molar mass of acetic acid (C2H4O2) is 60 g/mol. Therefore, there are 1 mole of acetic acid molecules in 60 g. Based on Avogadro's number (6.022 x 10^23 molecules/mol), there are approximately 6.022 x 10^23 molecules in 60 g of acetic acid.
How many kilojoules or energy are required to vaporize 5 g of ethane?
The heat of vaporization for ethane is approximately 16.7 kJ/g. Therefore, to vaporize 5 g of ethane, the energy required would be: 16.7 kJ/g * 5 g = 83.5 kJ.
How many molecules of ethane are present in 0.334g of C2 H6?
1. Given: mass = 0.334g of C2H6, CAtomicWeight = 12.01, HAtomicWeight = 1.008 Required: a. Molar Mass of Ethane b. Number of molecules of C2H6 in 0.334g of C2H6 Formula: a. (n = (2 x CAtomicWeight) + (6 x HAtomicWeight) b. mass x (1 mole / a ) x (6.022x1023 molecules / 1 mole) Solution: a. Molar Mass of Ethane n = (2 x 12.01) + (6 x 1.008) n = 24.02 + 6.0498 n = 30.0698 b. Number of molecules n = 0.334 x (1 mole / 30.0698 g) x (6.022x1023 molecules / 1 mole) n = 6.689x1021 molecules FINAL Answer: The are 6.689x1021 molecules in 0.334g of Ethane
How many liters of water vapor will be produced when 8 liters of ethane gas are burned completely?
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
How many liters of water vapor will be produced when 8 liters of ethane gas (C2H10) are burned completely?
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
What is the specific enthalpy of combustion of ethane?
The specific enthalpy of combustion of ethane is approximately -1560 kJ/mol.
How many molecules are there in 22.0 g of silver chloride?
22.0 g of silver chloride contain 0,918.10e23 molecules.
How many molecules are in 26.3 g of calcium hydroxide?
26.3 g of calcium hydroxide contain 2,054 molecules.
What molecules contain 60g of alcohol and 60g of water?
Ethanol molar mass: 46,07 gWater molar mass: 18 gAvogadro number: 6,02214129.10 ex.2346,07 g--------------Avogadro number=number of molecules60 g------------------xx = 60 . A/46,07 = 7,842.10 ex.23 molecules of ethanol18 g--------------Avogadro number=number of molecules60 g------------------xx = 60 . A/18 = 20,074.10 ex.23 molecules
How many molecules are in 32 g of SO2?
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
