315 Kg/M3 approx.
If a 20kg bag of cement=0.1m3 with 100 lots o 0.01 to 1m3 then you will need 12.5 bags per m3. So you need approx 11.5m3 of sand and 144 bags of cement (144 x 0.01 = 1.44m3) to give you a total of 12.94m3
there are 108 20kg bags of concrete to 1 cu mtr. If your making your own mix using dry mix concrete requiring cement and water, and your making a mix ratio of 5:1, then you divide 108 by 6 = 18. therefore: 18x20kg bags of cement to 1800kgs of dry concrete mix.
14.814813 m3
Usually for a design mix as per Indian Standards when the mix proportions are arrived for M25,the total cement consumption will be around 400 kg.From that the number of cement bags will be 8 numbers for 1 cum
1400 kg/m3
quantity of cement for M20 in one cubic metercement=1440 kg/m3sand=1700 kg/m3aggregate= 1600 kg/m3Lets solve for M20 i.e, 1:1.5:31 bag of cement = 50 kg =34.7 litres=35 litresi.e, 0.035 m3(item) (w/c ratio)(water) (cement)(sand)(aggregate)volume(0.42)(21ltr)(0.035)(0.0525)(0.105)voids - (0) (0) (0 60%) (40%) (45%)solidvolume (-) (0.021) (0.014) (0.0315) (0.05775) *sum=0.124Thus 50 kg of cement gives 0.124 m3 of concrete for M20 at 0.42 w/c ratio.Hence,cement required =0.035/0.124 =0.28 m3 i.e, 0.28*1440=403kgsand required= 0.0525/0.124 =0.42 m3 i.e, 0.42*1700 = 714 kgsimilarly aggregate required = 1360 kgwater required = 169 litreCheck: 403+714+1360 = 2477 i.e, density of concrete =2477kg/m3*NOTE: The quantity of cement, sand, aggregate & water varies with the w/c ratio and the density of materials.
1440kg/m3
1780kg/m3
The volume is(1000)/(density of cement in kg/m3) cubic meters.
The density of Portland cement is 1.44 ton/m3.
A 20 ft container = around 15 Tonnes... max payload21, 750 kilos for container with volume of 33.2 m3Stowage factor1.92 - 2.26 m3/t (jute bags, 60 - 65 kg) [1]2.00 - 2.15 m3/t (bags) [11]2.26 - 2.40 m3/t (bags) [14]