The question is not worded correctly. It should ask, what is the full load current for a 5 hp motor.
The correct answer is predicated on a few unknown factors.
#1. What is the user voltage?
#2. Is this a single phase or a three phase application?
Without those unknown values here is the N.E.C. Table "nominal" Ful Load Currents.
3 Phase: 230V = 15.2A 460V = 7.6A
1 Phase: 115V = 56A 230V = 28A
Keep in mind that the N.E.C. Tables are for nominal applications only. The National Electrical Code requires that you refer to the motor nameplate specifications for applying both short circuit and overload protection.
What is the continuous current of 10HP star delta motor
you need the current of motor or the KW/HP rating
To answer this question the voltage of the motor must be stated.
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
its depends upon rotor voltage and current
HP = (Current x Voltage)/746, or HP = (IE)/746 (disregarding %Efficiency) So, you have to solve for I, current: I = (746 x HP)/E
What is the continuous current of 10HP star delta motor
you need the current of motor or the KW/HP rating
For a single-phase induction motor, allow 7 amps on a 240 v for a 1-HP motor. Therefore the formula is: current = 7 X HP x 240 / voltage
current = power/ voltage current = 3700/ 240 = 15.4 amps
1 HP electric motor = 1.5 HP hydraulic motor so for a 3 HP electric motor you would need a 4.5 HP hydraulic motor. Also for your information a 1 HP hydraulic motor = 1 2/3 HP gasoline engine.
All motors draw less current when their load reduces.
190 cc. is about 5 hp.
you need around 60000 watts on a dc current
To answer this question the voltage of the motor must be stated.
200 hp requires about 149kW
roughly 342 cc's to a 12 hp engine