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Q: How many different type of organisms can be produced by genotype AAbb?
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How many different kinds gametes will an individual with genotype AAbb produce?

2 can


What is a heterozygous genotype for a dihybrid?

AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.


An individual with the genotype AaBb produces four different gametes in equal proportions This is a demonstration of?

law of independent assortment b


What will the percentage of a b gametes produced by Aa Bb parent?

If the genotype is AaBb then there will be 4 gametes produced: AB, Ab, aB, ab. Therefore the percentage of ab gametes is 25%


What word describes an organism that has the genotype Bb?

The most accurate description of an organism with genotype AaBb is heterozygous. A homozygous genotype is aaBB and AA.


A cross between organisms with the genotypes AaBb and AaBb called?

This is called a dihybrid cross in which both parents are heterogeneous.


What are all the possible gametes of an individual with the genotype Aabb?

Ab and ab There would be about a 50/50 ratio of each.


What are genotype and phenotype ratios for the dihybrid cross AaBB X AaBb?

The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1


What color is a person with AAbb genotype?

if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children


What is the phenotype of all four offspring's?

Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb


Where did the ratio 9331 come from include what each of these four numbers mean?

The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)


In the individual with genotype AaBB what percentage of gametes will contain the A allele?

You need to make a Punnet Square Put A and a on top and B and B on the left side. These represent the possible gametes. Your results should be: AB AB Ba (aB) Ba (aB) So 50% of the genotype have the A allele.