5 electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent.
yes
A blueshift is a change in the wavelength of light, in which the wavelength is shorter than it was when it was emitted at the source.
The temperature of the object.
jl
because when elements are heated there electrons become excited and jump through the elements "steps" and as they become less excited the jump back down steps emitting a unique wavelength and the visible wavelength is the colour we see -------------------------------------- The wavelength of the spectral lines emitted by different elements are specific for each element. Consequently the colour is also different.
This question can likely be answered using the formula E=hc/w where w is wavelength, h is Planck's constant, c is the speed of light, and E is energy in Joules. 5 electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent.
Because, due to the absorption of heat energy by the calcium atom in the flame. The electrons in the atom get promoted to a higher energy level, and exist in an unstable excited state. As they are unstable and prefer to be at their normal ground state, the extra energy that the electrons absorbed to be promoted in the first place is emitted in the form of a photon, light. The light emitted from the electrons of the calcium atoms will be at a specific wavelength, which is the red light you see emitted from the flame. Because, due to the absorption of heat energy by the calcium atom in the flame. The electrons in the atom get promoted to a higher energy level, and exist in an unstable excited state. As they are unstable and prefer to be at their normal ground state, the extra energy that the electrons absorbed to be promoted in the first place is emitted in the form of a photon, light. The light emitted from the electrons of the calcium atoms will be at a specific wavelength, which is the red light you see emitted from the flame.
The unit of fluorescence intensity is known as FUs. These are unitless and instead shows the light that is emitted from the longer wavelength.
yes
Visible light of a different frequency is a different color. Visible light of a higher frequency is closer to the violet end of the spectrum. If the frequency of a light source were increased, then the wavelength of its emission would decrease, because the product of (frequency) x (wavelength) is always the same number for all light in the same medium.
The more energy levels the electron jumps the more energy the emitted light will have. The more energy you have the shorter wavelength there is.
These are detemined by the band gap (a zone without electrons) of the solid used in LED.
In radiography electrons are emitted when x rays fall on the screen, while in fluoroscopy light is emitted.....the electrons emitted in radiography stabilize the silver ions in the film and hence get deposited as metallic silver.The amount of silver deposition is proportional to the amount of electrons liberated which is in turn proportional to the intensity of the x-rays that strike the film.
The photoelectric effect is based on two principles. 1. The intensity or brightness of the visible light (number of photons): The higher the intensity (larger number of photons) determines the number of electrons that are released from the surface material. 2. The frequency of visible light (wavelength): The higher the frequency a beam of light has when it strikes the surface determines the speed (kinetic energy) of the electrons that are ejected from the material. This is independent from light intensity. The higher the frequency of the light, the higher the energy of the electrons emitted, and thus, the higher the current of the circuit.
In the photoelectric effect, electrons are emitted from matter (metals and non-metallic solids, liquids or gases) as a consequence of their absorption of energy from electromagnetic radiation of very short wavelength, such as visible or ultraviolet light. Electrons emitted in this manner may be referred to as "photoelectrons"
Much shorter wavelength in UV light, hence much greater energy.
A blueshift is a change in the wavelength of light, in which the wavelength is shorter than it was when it was emitted at the source.