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The fluoride atom has 7 electrons in its outer shell (9 in total) but the ion of fluorine has any number of electrons in the outer shell. eg. F+ = the normal fluorine atom but with one less electron.
The highest energy shell of Fluorine is 2nd shell which contains 7 electrons just like other halogens.
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lose 3 electrons from its second shell
in a normal F- ion there are 10 electrons total (but 8 in the outer energy level)
A Fluorine atom has an atomic number of 9. Draw out the electron shell diagram for Fluorine. Is a Fluorine atom more likely to gain, lose or share electrons to fill its valence shell?
The fluoride atom has 7 electrons in its outer shell (9 in total) but the ion of fluorine has any number of electrons in the outer shell. eg. F+ = the normal fluorine atom but with one less electron.
The highest energy shell of Fluorine is 2nd shell which contains 7 electrons just like other halogens.
Each fluorine atom has 7 electrons in its outer shell, but a setup of 8 outer shell electrons (called an octet) is stable. To get this octet a fluorine atom will form a single covalent bond with another fluorine atom. Each atom give one electron to be shared between the two.
A fluorine atom that has seven electrons in its outer shell would be neutral. A negatively charged fluoride ion, Fl-, forms when a fluorine atom gains one electron so that it has an octet, or a noble gas configuration of electrons.
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A fluorine atom has seven unshared electrons in its outer most shell (valence shell).
The second shell can hold eight electrons.
lose 3 electrons from its second shell
Valence electrons of any atom are located in the outermost shell that atom carries electrons. For example a carbon atom has 6 electrons: 2e in its first shell (which is full) and 4e (valence electrons) in second shell--there are no electrons farther than second shell for carbon.
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