Probably you want the electron cofiguration of uranium: [Rn]5f36d17s2 The ion U4+ lost four electrons.
Yes it contains the lead (IV) ion.
CrO2this is the incorrect formula. For Chromium II oxide the formula is actually CrO without the 2. The reason for this is simple. the II after chromium indicates that it has a charge of +2, and the oxygen, we know is in group 16, has a charge of -2. The formula CrO2 is actually the formula for chromium IV oxide>
Balance the oxidation states on the atoms in the molecule. An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-. As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get CrO2 (which you can write as Cr4+ (O2-)2 )
lead IV chloride
how many proton and electron are in the tin IV ion
Probably you want the electron cofiguration of uranium: [Rn]5f36d17s2 The ion U4+ lost four electrons.
The formula for lead(IV) ion is Pb4+ and for nitrite ion is NO2-.
lead (IV) ion is Pb4+ ion. Note that Pb4+ is never found as an ion- the (IV) is an oxidation number or oxidation state.
Yes it contains the lead (IV) ion.
CrO2this is the incorrect formula. For Chromium II oxide the formula is actually CrO without the 2. The reason for this is simple. the II after chromium indicates that it has a charge of +2, and the oxygen, we know is in group 16, has a charge of -2. The formula CrO2 is actually the formula for chromium IV oxide>
That would be chromium(IV) selenide with the formula CrSe2
The Lead IV ion is Pb4+
Molybdenum (IV) phosphate's formula is: Mo3(PO4)4 Molybdenum (IV) has four valence electrons, which it will lose, being a metal. The phosphate polyatomic ion, PO4, needs three electrons. In order for the charges to cancel each other out, you need 3 Mo's and 4 phosphates, which you apply with the subscripts shown above.
Chromium (II) chloride = CrCl2Chromium (III) chloride = CrCl3 Chromium (IV) chloride = CrCl4
Lead IV is the 4+ ion formed by the element lead (Pb). Because Pb4+ is a positive ion it must be accompanied by a negative ion.
O2- ion is known as peroxide in English. As it is not a transition metal ion, it is not able to be written any other way. If it were a transition metal such as Lead (Pb), the Pb4+ ion can be called lead (IV) or plumbic. Lead (IV) is written in the Stock method with roman numerals representing the electrons in the ion. Plumbic is written in the Classical method with the suffixes "ic" and "ous". As some transition metals have two different ions, "ic" is added to the higher ion name while "ous" is added to the lower ion name.