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How many elements in C12h22o11?

Updated: 5/22/2024
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11y ago

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11y ago
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2w ago

There are 45 elements in C12H22O11.

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Q: How many elements in C12h22o11?
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Related questions

What are the elements of sugar and C12H22O11?

Table sugar is a compound with the molecular formula C12H22O11 , meaning that there are 3 different elements (bold letters) in that molecule:12 atoms of carbon (C)22 atoms of hydrogen (H)11 atoms of oxygen (O)


How many g of CO2 is produced per g of c12h22o11?

11 g of CO2 is produced per 1 g of C12H22O11 through the combustion reaction process.


How many Total no of atoms present in C12H22O11?

The total no. of atoms present in C12H22O11 is 45.


What is C12H12O11 known as?

in c12h22o11 there are 12 carbon atoms 22 hydrogen atoms and 11 oxygen atoms therefore there are 48 atoms altogether by CALEB AMETEPEY GOMADO NEW NATION


How many carbon atoms are in C12H22O11?

12


What is the ratio of C12H22O11?

The ratio of C12H22O11 to WHAT!


What is the name for C12H22O11?

The name for C12H22O11 is sucrose, which is a common type of sugar found in many plants.


How many C H O are in sucrose?

C12H22O11


How many atoms does table sugar have?

A molecule of table sugar (sucrose) has 45 atoms: 12 atoms of carbon, 22 of hydrogen, and 11 of oxygen.


How many oxygen atoms are in one molecule of C12H22O11?

11


How many carbon atoms are in 10 pounds of C12H22O11?

To find the number of carbon atoms in 10 pounds of C12H22O11, you need to first calculate the molar mass of C12H22O11. Then, you can convert 10 pounds to grams and use the molar mass to find the number of moles of C12H22O11. Finally, since there are 12 carbon atoms in each molecule of C12H22O11, you can multiply the number of moles by Avogadro's number to find the number of carbon atoms.


How many oxygen atoms are there in 17.1g of sucrose?

The formula with this disaccharide is, C12H22O11 17.1 grams C12H22O11 (1 mole C12H22O11/342.296 grams)(11 mole O/1 mole C12H22O11)(6.022 X 10^23/1 mole O) = 3.31 X 10^23 atoms of oxygen ------------------------------------------