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How many formula units are there in one-half mole of ammonium sulfate?
Wiki User
∙ 12y ago
One-half of Avogadro's Number, or about 3.011 X 1023.
Wiki User
∙ 12y ago
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How many moles of ammonium ions are in 8.903 g of ammonium carbonate?
The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.
How many formula units are there in 0.0482 mol of sodium sulfate?
0.0482 moles Na2SO4 x 6.02x10^23 form.units/mole = 2.91x10^22 formula units
How many ammonium ions are present in 10.7g of ammonium phosphate?
The formula for the most common form of ammonium phosphate is (NH4)3PO4.3 H2O, and its gram formula mass is 203.13. The formula shows that there are 3 ammonium ions in each formula unit. 10.7g/203.13 is 5.27 X 10-2 formula units. Therefore, the number of ammonium ions present in 10.7g of this ammonium phosphate is 3 X 5.27 X 10-2 X Avogadro's Number or 9.52 X 1019 ammonium ions, to the justified number of significant digits.
How many atoms of aluminum sulfur and oxygen are in 3 molecules of aluminum sulfate?
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
How many moles of formula units are in 5.67g of iron sulfate?
1.42 x 10^-2 mole
How many moles of ammonium ions are in 8.903 g of ammonium carbonate?
The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.
How many moles of formula units are in 5.67 g of iron III sulfate?
There is 1.42 x 10^-2 moles of formula units that are in 5.67 g of iron III sulfate.
How many formula units are in 5.38 moles of potassium sulfate?
The answer is 32,4.10e23.
How many formula units are there in 0.0482 mol of sodium sulfate?
0.0482 moles Na2SO4 x 6.02x10^23 form.units/mole = 2.91x10^22 formula units
How many ammonium ions are present in 10.7g of ammonium phosphate?
The formula for the most common form of ammonium phosphate is (NH4)3PO4.3 H2O, and its gram formula mass is 203.13. The formula shows that there are 3 ammonium ions in each formula unit. 10.7g/203.13 is 5.27 X 10-2 formula units. Therefore, the number of ammonium ions present in 10.7g of this ammonium phosphate is 3 X 5.27 X 10-2 X Avogadro's Number or 9.52 X 1019 ammonium ions, to the justified number of significant digits.
How many atoms of aluminum sulfur and oxygen are in 3 molecules of aluminum sulfate?
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
What are the formula units for sodium sulfide sodium sulfite and sodium sulfate?
Sodium sulfide: Na2S Sodium sulfite: Na2SO3 Sodium sulfate: Na2SO4
Do All sulfate minerals have an SO4 in their chemical formula?
Yes, they have one or more SO4-2 units.
How many moles of formula units are in 5.67g of iron sulfate?
1.42 x 10^-2 mole
What is the mass in grams of 3.52 mol of iron2 sulfate?
The formula for iron (II) sulfate is FeSO4.H2O, and its gram formula unit mass is 169.92. Therefore, 3.52 formula units of this compound have a mass of 598 grams, to the justified number of significant digits.
What is the mass of 43mol of sodium sulfate?
The gram formula mass of anhydrous sodium sulfate is 142.04. Therefore, 43 gram formula units* of it has a mass of 43(142.04)6.1 X 103 grams, to the justified number of significant digits. _____________________________ For ionic compounds such as sodium sulfate, the term "formula unit" is preferred to "mole".
What is the number of formula units in 2.25 moles of ammonium chlorate?
Easy stuff. Take the number of moles given and multiply it by Avogadro's constant, which is 6.02x1023. That number represents the number of representative particles of any substance. So, 2.25 times that number gets you 13.55x1023, which you must adjust to 1.4x1024 formula units of ammonium chlorate (NH4ClO3).
