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Sodium chloride "formula units" form a very large lattice.
The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.
The formula unit for lead (II) chloride is Pb(NO3)2. This formula shows that each formula unit contain one lead (II) ion. By the definition of molarity, a liter of a 0.250 molar solution of lead (II) nitrate therefore contains 0.25 gram formula units of lead (II) ions per liter of solution, so that 250 milliliters of such a solution will contain 250/1000 of this amount, or 0.0625 gram formula units. Assuming that chlorine is an ideal gas, 22.4 liters of it at STP contain one mole. Since gases are homogeneous, 14.6 liters of it will contain 14.6/22.4 or 0.652 moles. The formula of gaseous chlorine at STP is Cl2. Therefore, 0.652 moles of it contain twice this number of chlorine atoms, or 1.305 "moles" of such atoms. The formula unit for lead (II) chloride is PbCl2. Therefore, each gram formula unit of lead (II) requires two gram formula units of chloride ions. Comparison shows that there is a large excess of chlorine over that required to form lead (II) chloride from the 0.0625 gram formula units of lead (II) contained in the specified amount of solution. Lead (II) is therefore the limiting reagent in this combination, and 0.0625 gram formula units of PbCl2 can be produced. The gram atomic mass of lead is 207.2 and that of chlorine is 35.453. Therefore, the mass of lead (II) chloride that can be produced is 0.0625[207.2 + 2(35.453)] or 17.4 grams, to the justified number of significant digits.
10 formula units
Iodine is 127 and Magnesium is 24 so the difference is 103 atomic mass units.
0,355 formula units make up 33,8 g of magnesium chloride (MgCl2).
Approx. 3 formula units (the molar mass of the anhydrous MgCl2 is 95,211).
The molar mass of magnesium chloride is 95,211 g.25,6/95,211 = 0,269
32,2 g is 0,338 from the formula unit.
Magnesium chloride (MgCl2) has a molecular weight of 95.21 grams per mole. 11.6 grams of MgCl2 is therefore .122 moles.
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
12.2/95.211 = .1281 moles MgCl2. .1281 x 6.022x1023 = 7.7177x1022 molecules
MgCI2 does not exist. The formula is MgCl2 with a lowercase L. This compound is ionic.
formula units
The gram formula unit mass of magnesium chloride is 95.21. Therefore, 21.2g of magnesium chloride make up 21.2/95.21 or 0.223 formula units, to the justified number of significant digits.
No: Each "mole", more precisely called "formula mass", of sodium chloride contains two ions, as shown by its formula NaCl, but each formula mass of magnesium chloride has three ions as shown by its formula MgCl2. This is true because sodium cations have only one positive electric charge unit, magnesium cations have two electric charge units, and chloride ions have one negative electric charge unit each.