10 formula units
The answer is 5,978 moles.
The answer is 32,4.10e23.
The answer is 2,09 moles.
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
A formula unit of salt, such as sodium chloride (NaCl), represents one mole of the compound. Therefore, if you have 10 moles of salt, you have 10 formula units of NaCl. In other words, for every mole of salt, there is one corresponding formula unit. Thus, 10 moles of salt correspond to 10 formula units.
The answer is 5,978 moles.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
The answer is 32,4.10e23.
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
42.394 grams.
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
The answer is 2,09 moles.
(2.3 x 10^23) / (6.02 x 10^23) =0.38 moles
To determine the number of formula units in 2.45 moles of potassium chloride, you first need to find the molar mass of KCl, which is approximately 74.55 g/mol. Then, divide the number of moles by the molar mass to get the number of formula units. Therefore, 2.45 moles of KCl is equivalent to about 163 formula units.
There are 1.96 x 10^24 formula units in 3.25 moles of silver nitrate. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of the compound.
A formula unit of salt, such as sodium chloride (NaCl), represents one mole of the compound. Therefore, if you have 10 moles of salt, you have 10 formula units of NaCl. In other words, for every mole of salt, there is one corresponding formula unit. Thus, 10 moles of salt correspond to 10 formula units.
There are 3.01 x 10^24 formula units of CaCl2 in 2.50 moles. This can be calculated using Avogadro's number (6.022 x 10^23) and the formula units present in one mole of CaCl2 (3).