671
AlPO4 6.5 moles AlPO4 (121.95 grams/1 mole AlPO4) = 792.675 grams of AlPO4 ( you do sigi figis )
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
72
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
Because the atomic mass of aluminum is 26.99, this means that there are 26.99 grams of aluminum in one mole. For 3 moles multiply 26.99 by 3 = 80.97grams.
The answer is 902,45 g.
AlPO4 6.5 moles AlPO4 (121.95 grams/1 mole AlPO4) = 792.675 grams of AlPO4 ( you do sigi figis )
1,99 grams of aluminum is equal to 0,0737 moles.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
72
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
200
Because the atomic mass of aluminum is 26.99, this means that there are 26.99 grams of aluminum in one mole. For 3 moles multiply 26.99 by 3 = 80.97grams.
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles