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How many grams in 6.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many grams of aluminum would be in 3.0 moles of aluminum?
The molar mass of aluminum is approximately 27.0 g/mol. To find the mass of 3.0 moles of aluminum, you can multiply the number of moles by the molar mass: 3.0 moles * 27.0 g/mol = 81.0 grams of aluminum.
6.7 grams of aluminum sulfate to moles?
To convert grams of aluminum sulfate to moles, you first need to determine the molar mass of aluminum sulfate (Al2(SO4)3), which is approximately 342.15 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 6.7 grams of aluminum sulfate is approximately 0.02 moles.
What is 18.32 grams of aluminum and excess oxygen how many grams of aluminin oxiode are preduced?
Given the balanced chemical equation: 4Al + 3O2 → 2Al2O3, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. In this case, 18.32 grams of aluminum is equivalent to 0.684 moles. Using stoichiometry, we find that this would produce 0.456 grams of aluminum oxide.
How many grams in 6.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
Convert the number of grams in 7.4 moles of aluminum phosphate?
The answer is 902,45 g.
How many moles of aluminum are in 1.99 grams of aluminum?
1,99 grams of aluminum is equal to 0,0737 moles.
How many moles of aluminum are in 10grams of aluminum?
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many moles are 4.12 grams aluminum sulfate?
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
How many grams are in 0.658 mole of calcium phosphate?
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
How many grams of aluminum would be in 3.0 moles of aluminum?
The molar mass of aluminum is approximately 27.0 g/mol. To find the mass of 3.0 moles of aluminum, you can multiply the number of moles by the molar mass: 3.0 moles * 27.0 g/mol = 81.0 grams of aluminum.
The mass in grams of 2.8 moles aluminum?
200
6.7 grams of aluminum sulfate to moles?
To convert grams of aluminum sulfate to moles, you first need to determine the molar mass of aluminum sulfate (Al2(SO4)3), which is approximately 342.15 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 6.7 grams of aluminum sulfate is approximately 0.02 moles.
What is 18.32 grams of aluminum and excess oxygen how many grams of aluminin oxiode are preduced?
Given the balanced chemical equation: 4Al + 3O2 → 2Al2O3, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. In this case, 18.32 grams of aluminum is equivalent to 0.684 moles. Using stoichiometry, we find that this would produce 0.456 grams of aluminum oxide.
