The answer is 902,45 g.
To convert grams of aluminum to moles, you need to divide the given mass (5 g) by the molar mass of aluminum (26.98 g/mol). Therefore, 5 g of aluminum is equal to 5/26.98 = 0.185 moles of aluminum.
Thast is one mole. 26.98 grams/per mole is the mass.
9.4 grams
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
To calculate the number of atoms in 16.2 grams of aluminum, you first need to determine the number of moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of aluminum atoms in 16.2 grams.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
To convert grams of aluminum sulfate to moles, you first need to determine the molar mass of aluminum sulfate (Al2(SO4)3), which is approximately 342.15 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 6.7 grams of aluminum sulfate is approximately 0.02 moles.
To convert grams of aluminum to moles, you need to divide the given mass (5 g) by the molar mass of aluminum (26.98 g/mol). Therefore, 5 g of aluminum is equal to 5/26.98 = 0.185 moles of aluminum.
To find the number of aluminum atoms in 30 grams, you first need to determine the number of moles of aluminum using its molar mass (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
Thast is one mole. 26.98 grams/per mole is the mass.
9.4 grams
To calculate the number of aluminum atoms in 3.24g of aluminum, first find the molar mass of aluminum, which is 26.98 g/mol. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Divide 3.24g by the molar mass of aluminum and then multiply by Avogadro's number to find approximately 3.01 x 10^22 atoms of aluminum in 3.24g.
To convert milligrams to grams:1 gram = 1000 milligramsSo take the number of milligrams and divide by 1000 to get the number of grams.To convert grams to milligrams:Take the number of grams and multiply by 1000 to get the number of milligrams.Examples:500 milligrams = 0.5 grams2 grams = 2000 milligrams
To determine the number of molecules in 2.0 grams of aluminum chloride, first calculate the molar mass of aluminum chloride (AlCl3). The molar mass is 133.34 g/mol. Next, convert the given mass (2.0 g) to moles using the molar mass. Finally, use Avogadro's number (6.022 x 10^23) to find the number of molecules.