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How many moles are contained in 86.6 grams in sodium bicarbonate?
Sodium Bicarbonate = NaHCO3 Molecular weight = Summation of individual molecular weights of elements =[(1)(22.99 g/mol) ] + [(1)(1.01 g/mol)] + [(1)(12.01 g/mol)] + [(3)(15.99 g/mol)] =84.01 g/molSo,(86.6 g) / (84.01 g/mol) = 1.031 mol
How many moles of NaHCO3 are present in 3.00 g sample?
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
What is 2.00 grams of baking soda in moles?
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams2.00 grams NaHCO3 / (84.0 grams) = .0238 moles NaHCO3
How many grams of H2O do you need to weigh out to have 1 mole of H2O?
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
What is the conversion factor from grams per mole (g/mol) to daltons?
The conversion factor from grams per mole (g/mol) to daltons is 1 g/mol 1 dalton.
How many moles are contained in 86.6 grams in sodium bicarbonate?
Sodium Bicarbonate = NaHCO3 Molecular weight = Summation of individual molecular weights of elements =[(1)(22.99 g/mol) ] + [(1)(1.01 g/mol)] + [(1)(12.01 g/mol)] + [(3)(15.99 g/mol)] =84.01 g/molSo,(86.6 g) / (84.01 g/mol) = 1.031 mol
What is the solute mass of NaHCO3 if mol solute is 0.025 volume solution is 0.25 liters and molarity 0.100M?
All you need is the moles and the mass of NaHCO3 and you have the moles 0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 2.1 grams of sodium bicarbonate ---------------------------------------------
How many moles of NaHCO3 are present in 3.00 g sample?
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
How many moles of NaHCO3 are present in a 6.10 g sample?
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
What is 2.00 grams of baking soda in moles?
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams2.00 grams NaHCO3 / (84.0 grams) = .0238 moles NaHCO3
How many grams of H2O do you need to weigh out to have 1 mole of H2O?
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
If 5 grams of NaHCO3 decomposes what is the mass of the carbon dioxide used?
I just had this question on my chem homework so I'll see if I can help. First thing you need to do is balance the equation. The balanced equation should look like this: 2NaHCO3 -----> Na2CO3 + H2O +CO2 With that out of the way we can start converting. The Molar Mass of NaHCO3 is 84 (or close to it, depending on how you round your decimals) So we do 5g NaHCO3/ 84g NaHCO3. That should give you about 0.059. Next we do 0.059/2mol NaHCO3, because we know from the balanced equation that we have a 2:1:1:1 ratio. That should give you about 0.0295. Now we find the Molar Mass of CO2, which is around 44. Lastly, we go 0.0295x44 and that should give us the answer. I got 1.3g of CO2 as my answer. I hope I was able to be of some use. :)
How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
5.8 grams in 1 liter of water equals how many moles?
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
What is the conversion factor from grams per mole (g/mol) to daltons?
The conversion factor from grams per mole (g/mol) to daltons is 1 g/mol 1 dalton.
How many grams of carbon are in 1.00 mol of carbon?
moles = mass/relative atomic mass 1 = mass/12 mass = 12 x 1 = 12 grams
