For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams
2.00 grams NaHCO3 / (84.0 grams) = .0238 moles NaHCO3
There are approximately 200 teaspoons in 1 kilogram of baking soda.
To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
There are approximately 200 teaspoons in 1 kilogram of baking soda.
To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
200
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
There are 200 grams in 200 grams.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
Well, darling, to find the number of formula units in 200 grams of Calcium Carbonate, you first need to calculate the molar mass of CaCO3. Once you do the math, you'll find that one mole of CaCO3 weighs 100.09 grams. So, 200 grams of CaCO3 represents 2 moles of the compound, which is equivalent to 2 times Avogadro's number (6.022 x 10^23) formula units. Voilà!