For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. CO2=44.0 grams
33.0 grams C / (44.0 grams) = .750 moles CO2
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
Carbon dioxide: CO2. The number to the right of the symbol for an element indicates how many atoms of that element are present in single molecule. If there is no number then there is one atom present. Then in the case of carbon dioxide there must be one atom of carbon (C) and two atoms of oxygen (O). Double these to provide the numbers of atoms of the two elements in two molecules: two of carbon, four of oxygen.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
Oxygen is present in many compounds, such as water (H2O), carbon dioxide (CO2), and oxides like rust (Fe2O3). It is also found in organic molecules like glucose (C6H12O6) and proteins.
molecular weight of carbon dioxide = 44u gram molecular weight of carbon dioxide = 44g given mass = 11g no. of moles = given mass divided by molar mass = 11 divided by 44 = 0.25moles.
8.066
2.65 mol * 64.07 g/mol = 169.79 g
The number of molecules is 0,90332112855.10e23.
2.75 x 1024molecules of CO2
The number is zero.No CO2 is produced in glycolisis.
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2
4
6
6 CO2 + 6 H2O →C6H12O6 + 6 O2Carbon dioxide + Water + Light energy → Glucose + Oxygen6 molecules of CO2
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.