# How many grams are in 3 mole of h2o?

A gram-mole is one gram times the molecular weight.

For water the molecular weight is 2 of hydrogen and 1 of oxygen = 2x1+1x16 = 18 so a gram-mole of water weighs 18 grams.

### How many moles are in 35.1 grams of water?

To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O

### How many liters of oxygen would be produced by the decomposition of 100 grams of H2O?

Let us assume for convenience that this reaction is at STP.( standard temperature and pressure ) Get moles O. 100 grams H2O (1 mole H2O/18.016 grams)(1 mole O/1 mole H2O) = 5.551 moles oxygen Now, the ideal gas law. PV = nRT (1 atm)(Vol L) = (5.551 moles O)(0.08206 L*atm/mol*K)(298.15 K) = 136 Liters of oxygen ----------------------------- Now, another way using oxygens density. Density = grams/milliliters 100 grams H2O (1 mole H2O/18.016 grams)(1 mole O/1…

### How many atoms of oxygen are there in 18 grams of water?

To convert from grams to atoms, we need 1) the molar mass, 2) The mole ratio between oxygen in water and water itself, and 3) The number of atoms in a mole. The molar mass of water is 18.02 grams/mole (H2O -> 1.01 + 1.01 + 16.00). For every one mole of H2O, there is one mole of oxygen, so that part is easy. The number of atoms in a mole is also known as…

### How many atoms are in 10.0 grams of water?

A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.

### How many moles of water are there in 100 grams of water?

1 molecule of water is composed of: H2, with a molar mass of 2.02g, assuming 3 significant digits. O, with a molar mass of 16.0g, assuming 3 significant digits. Therefore, 1 mole of water (H2O) molecules has a mass of 18.0g, keeping 3 significant digits. Then you just divide 100g by 18g, getting 5.555555... You must keep the 3 significant digits from before, though, so you round to 5.56. Your answer is 5.56 moles of…

### What is the unit of a mole?

A mole can mean three thing: 1) A number, like a dozen- and it is a unit, mol. 1 mol=6.02x1023. Ex: 1 mol of H2O atoms is 6.02x1023 H2O atoms. 2) At standard temperature and pressure, (STP), 1 mol=22.4 L. (liters) Ex: 1 mole of H2 gas a STP= 22.4 L. 3) The mass, in grams, of one mole of a molecule, atom, or ionic compound. Ex: 1 mole of CO2=44g because CO2 has a…

### How many protons are there in 134 grams of iron III hydrogen phosphate?

Fe2(HPO4)3 Four different species! Will need number atoms every species as protons vary. What a lot of work! In order. 134 grams Fe2(HPO4)3 (1 mole Fe2(HPO4)3/399.634 grams)(2 mole Fe/1 mole Fe2(HPO4)3)(6.022 X 1023/1 mole Fe) = 4.04 X 1023 atoms iron * 26 protons = 1.05 X 1025 protons iron -----------------------------------------------------======================-----------------------------------------------============== 134 grams Fe2(HPO4)3/399.634 grams)(12 mole O/1 mole Fe2(HPO4)3)(6.022 X 1023/1 mole O) = 2.42 X 1024 atoms oxygen * 8 protons = 1.94 X…

### Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?

2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we…

### If 1.25 grams of pure CaCO3 required 25.5 mL of a HCl solution for complete reation what is the molarity for the HCl solution?

When calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) the reaction is:- CaCO3 + 2 HCl -> CaCl2 + H2O + CO2 The weight for 1 mole of calcium carbonate is the atomic weight in grams or 40.8 + 12.011 + 3 x 15.9994 = 100.8092 grams 1.25 grams of CaCO3 is therefore 1.25/100.8092 or .0124 mole There must have been twice this many moles of HCl in the solution or 0.0248 mole. The molarity…

### How many moles of carbon atoms are there in 3 grams of carbon?

3 grams carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C)(1 mole C atoms/6.022 X 10^23) = 0.25 moles of carbon atoms ------------------------------------- ( as you may see this is a formal set-up and Alessandro's number is over itself in a form of one, so the first ratio, mole/gram, is all that is needed here )

### How do you calculate number of ions in 10 grams of AlCl3?

10 grams of AlCl3 contains a certain number of moles in particles. 1 mole of AlCl3 weighs (26.9815386+(3*35.453)=133.3405386), let's round that to 133.3405 grams. So 10 grams = 10/133.3405 = 0.075 mole of AlCl3 (rounded), but for each AlCl3 we have, you get 4 ions (1 Al3+, 3Cl-). So we have 0.075 moles, but we get 4 times as many ions. 0.075*4=0.3 mole 1 mole = 6.022141x1023 (Avogadro's Number) 0.3 mole = 1.81x1023 ions

### What mass of water is produced from the complete combustion of 1.10 and times10 and minus3 g of methane?

Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2O moles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 moles moles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 moles mass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)

### How many grams of H2 are needed to produced 10.14 grams of NH3?

Ammonia is formed by the following: N2 + 3H2 --> 2NH3 (1) Convert grams of ammonia to moles of ammonia using its molecular weight (17 g /mole) 10.14 g NH3 / (17 g NH3/mole NH3) = 0.597 moles NH3 (2) Now, using the reaction from above we see that for every mole of ammonia formed that 3 moles of hydrogen gas are used. Assuming that the reaction is in stoichemtric proportions you can figure out…