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Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
This is based on ammonia. There are 25 h grams.
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
2g
The mass of ammonia is 339,7 g.
Approx. 37 g ammonia can be dissolved.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
150 grams NH3 (1 mole NH3/17.034 grams)(3 mole H/1 mole NH3)(1.008 grams/1 mole H)= 26.6 grams hydrogen=================17 g of ammonia has 3 g of hydrogen.So 150 g of ammonia will have 26.5 g of hydrogen
16.0 g
7,02 g ammonia
The answer is 20,664 g ammonia.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
This is based on ammonia. There are 25 h grams.
200 grams = 0.2 kilograms
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
200 grams X 0.10 = 20 grams
2g