319g Cl2 are needed.
moles = weight in grams / molecular weight = 59.1 / 119.38 = 0.5 moles
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
215 g of chloroform is equal to 1,8 moles.
The needed mass of sodium is 91,659 g (for 2 moles H2).
(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!
moles = weight in grams / molecular weight = 59.1 / 119.38 = 0.5 moles
800 g oxygen are needed.
0.125 mole
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
215 g of chloroform is equal to 1,8 moles.
The needed mass of sodium is 91,659 g (for 2 moles H2).
(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!
This depends on the compound.
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
This is based on calculations too. It contains 18 hydrogen moles.
1.68