The molar mass of acetic acid is 60,05 g.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
60.06g
1 mole H2SO4 = 98.078g H2SO4
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
60
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
2
60.06g
The chemical reaction is: One mole of aspirin plus one mole of water yields one mole of salicylic acid plus one mole of acetic acid. Aspirin=C9H8O4 Salicylic acid=C7H6O3 Acetic acid=C4H6O3
1 mole H2SO4 = 98.078g H2SO4
Acetic Acid, CH3COOH, has a molecular weight of 60.05
1 mole to 1 mole NaOH
63 if it is anhydrous