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What weight of nitric acid can be produced from 18.5 gram of nitrogen dioxide?
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
How many grams would be in four 4 moles of nitric acid HNO3?
The molar mass of nitric acid (HNO3) is 63.01 g/mol. To find the total grams in 4 moles, you would multiply the molar mass by the number of moles: 63.01 g/mol x 4 mol = 252.04 grams. So, there would be 252.04 grams in four moles of nitric acid (HNO3).
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How many grams are in 1 mole of sulfuric acid?
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
What is the maximum mass of Nitric Acid which would be required to react with 0.35 grams of copper metal?
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
What weight of nitric acid can be produced from 18.5 gram of nitrogen dioxide?
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
How many grams would be in four 4 moles of nitric acid HNO3?
The molar mass of nitric acid (HNO3) is 63.01 g/mol. To find the total grams in 4 moles, you would multiply the molar mass by the number of moles: 63.01 g/mol x 4 mol = 252.04 grams. So, there would be 252.04 grams in four moles of nitric acid (HNO3).
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How many grams are in 1 mole of sulfuric acid?
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
What is the maximum mass of Nitric Acid which would be required to react with 0.35 grams of copper metal?
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
How many grams is in one mole of acetic acid?
The molar mass of acetic acid is 60,05 g.
How much does one gallon of nitric acid weigh?
Nitric acid has the formula of HNO3. It has a density of 1.5129 grams per cubic centimeter. This means that 2500 cubic centimeters has a mass of 3.78 kilograms.
What is the molarity of nitric acid?
The molarity of nitric acid, HNO3, can vary depending on the concentration of the solution. For example, a 1 M solution of nitric acid would contain 1 mole of HNO3 per liter of solution. It is important to know the concentration or volume of the solution to determine the molarity of nitric acid.
How many moles of magnesium nitrate are produced when magnesium reacts with 8 moles of nitric acid?
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
How many grams are 0.7 mole of hydrochloric acid?
This mass is 25,522 g.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
To neutralize the nitric acid, you need a 1:1 mole ratio of sodium hydroxide to nitric acid. First, calculate the moles of nitric acid in the solution using the formula Molarity = moles/volume. Then, use the mole ratio to find the moles of sodium hydroxide needed. Finally, convert this to grams using the molar mass of sodium hydroxide.
What is the heat of neutralization of nitric acid?
The heat of neutralization of nitric acid refers to the amount of heat released when one mole of nitric acid is neutralized by a base to form water and a salt. For strong acids like nitric acid, the heat of neutralization is typically around -57.3 kJ/mol.
