Acetic Acid, CH3COOH, has a molecular weight of 60.05
CH3COOH CH3COO- + H+So there is only one acidic H atom.[Only the 'bold' H atom is acidic, the 3 'methyl' H's are not!]
To make Sodium Acetate, you would typically mix one mole of acetic acid (CH3COOH) with one mole of sodium hydroxide (NaOH). This will result in the formation of one mole of sodium acetate (CH3COONa) along with water. The balanced chemical equation for this reaction is CH3COOH + NaOH -> CH3COONa + H2O.
The molar mass of acetic acid is 60,05 g.
The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol. Therefore, the mass of one mole of acetic acid is 60.05 grams.
CH3COOH (acetic acid) is considered a monobasic acid because it can donate only one proton (H+) per molecule in a chemical reaction. This means that it has only one hydrogen atom that can dissociate, forming one hydronium ion (H3O+) in solution.
CH3COOH CH3COO- + H+So there is only one acidic H atom.[Only the 'bold' H atom is acidic, the 3 'methyl' H's are not!]
To make Sodium Acetate, you would typically mix one mole of acetic acid (CH3COOH) with one mole of sodium hydroxide (NaOH). This will result in the formation of one mole of sodium acetate (CH3COONa) along with water. The balanced chemical equation for this reaction is CH3COOH + NaOH -> CH3COONa + H2O.
The molar mass of acetic acid is 60,05 g.
The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol. Therefore, the mass of one mole of acetic acid is 60.05 grams.
CH3COOH (acetic acid) is considered a monobasic acid because it can donate only one proton (H+) per molecule in a chemical reaction. This means that it has only one hydrogen atom that can dissociate, forming one hydronium ion (H3O+) in solution.
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
carbon oxygen hydrogen = CH3COOH is the thingy for vinegar
It is CH3COOH
Ch3coo(-) + h2o ---> ch3cooh + oh(-)
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
AnswerThis is the energy change which occurs when 1 mole of water is formed during a neutralization reaction between an acid and an alkali