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Acetic Acid, CH3COOH, has a molecular weight of 60.05

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12y ago

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How many hydrogen atoms are present in 1 mole of acetic acid or CH3COOH?

CH3COOH CH3COO- + H+So there is only one acidic H atom.[Only the 'bold' H atom is acidic, the 3 'methyl' H's are not!]


What is the ratio of Na-OH and Acetic Acid to make Sodium Acetate?

To make Sodium Acetate, you would typically mix one mole of acetic acid (CH3COOH) with one mole of sodium hydroxide (NaOH). This will result in the formation of one mole of sodium acetate (CH3COONa) along with water. The balanced chemical equation for this reaction is CH3COOH + NaOH -> CH3COONa + H2O.


How many grams is in one mole of acetic acid?

The molar mass of acetic acid is 60,05 g.


What is the mass of one mole of acetic acid?

The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol. Therefore, the mass of one mole of acetic acid is 60.05 grams.


Why is CH3COOH is monobasic acid?

CH3COOH (acetic acid) is considered a monobasic acid because it can donate only one proton (H+) per molecule in a chemical reaction. This means that it has only one hydrogen atom that can dissociate, forming one hydronium ion (H3O+) in solution.


What is the conjugate base of CH3COOH?

The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).


Vinegar contains acetic acid. The formula for acetic acid is CH3COOH. One mole of acetic acid has a mass of how many grams?

The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole


What is the chemical symbol for vinegar?

carbon oxygen hydrogen = CH3COOH is the thingy for vinegar


What is the acitic acid formula?

It is CH3COOH


What is the product of CH3COOH plus (C2H5)2O?

Ch3coo(-) + h2o ---> ch3cooh + oh(-)


How many grams of CH3COOH are needed to make 3.4 liters of aqueous solution of pH equals 4.0?

Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )


What is heat of neutralization of nh4oh and ch3cooh?

AnswerThis is the energy change which occurs when 1 mole of water is formed during a neutralization reaction between an acid and an alkali