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2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
Br-80 has 35 protons.
TOTAL PRODUCTION: 115 BUILDER: BR Horwich (45), Doncaster (25), and Derby Works (45)
7
The neutral atom has 35 electrons.
1st you must find the molar mass of CaBr2. Ca 40.08g * (number of moles in the compound) 1 Br 79.90g * 2 This give you the amount (g) in 1 mole of CaBr2. Multiply by 14 and you get the answer.
CaBr2 will dissociate into Ca2+ ions and two Br- ions. In aqueous solution of CaBr2, water is the solvent and Ca2+ ions and Br- ions are the solute particles.
All you have to do is flip the numbers and reduce. If you have Ca+2 and Br-, Switch the numbers so you get CaBr2. 1 and 2 do not have any common factors so you don't have to reduce! CaBr2 is the final answer.
The ionic compound calcium bromide is CaBr2.
Ca2+ and Br- obviously must form, CaBr2 Calcium bromide
Ca+2 + Br-1 --> CaBr2 (calcium bromide)
CaBr2
Fe (III) has a charge of 3+. Br has a charge of 1-. This means that in order to make the overall charge of the ionic compound of Iron III and Bromine, there must be one atom of Iron III and three atoms of Bromine. This makes the formula FeBr3.
445 g
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
We know that the alkaline earth metal calcium (Ca) and the halogen bromine (Br) form the ionic compound calcium bromide (CaBr2). Here's the reaction: Ca + 2Br => CaBr2
Ionic bonding. Ca 2+ and 2Br - CaBr2