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The answer is 445,6 g carbon dioxide.

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How many grams of CO2 can 580.0 grams of LiOH absorb?

The molar mass of LiOH is 23.95 g/mol for lithium, 15.999 g/mol for oxygen, and 1.008 g/mol for hydrogen, totaling 41.943 g/mol for LiOH. This means that for every 41.943 grams of LiOH, 44.01 grams of CO2 can be absorbed. To find out how much CO2 can be absorbed by 580.0 grams of LiOH, you can set up a simple ratio and cross-multiply to get your answer.


How many grams of Li OH are present in 8.0 mL of a 7.0 percent NaOH solution?

To find the grams of LiOH in the solution, we need to use the percentage concentration of NaOH to calculate the molarity of the solution first. Then, we can use stoichiometry to convert the moles of NaOH to LiOH since they are in a 1:1 ratio. Finally, we can convert the moles of LiOH to grams using its molar mass.


How many grams of carbon dioxide can be absorbed by 1 gram of lithium hydroxide?

Two moles of LiOH may absorbe one mole of CO2 that means 47.9g LiOH may absorbe 44.01g CO2 so 1 g may absorbe 44.01 divided by 47.9 = 0.919 g. 2LiOH + CO2 = Li2CO3 + H2O


How many grams of LiOH is formed from 25.0 g of CaOH given the following equation... Ca(OH)2 plus Li2CO3 ----- and gt CaCO3 plus 2Li(OH) What is the answer and how did you get it?

The chemical reaction is:Li2CO3 + Ca(OH)2 = 2 LiOH + CaCO3Molar maass of LiOH is 23,95 g; molar mass of calcium hydroxide is 74,093 g.74,093 g Ca(OH)2----------------2.23,95 g LiOH25 g Ca(OH)2----------------------xx = (25 x 2 x 23,95)/74,093 = 16,2 g LiOH


Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?

Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)


A chemical reaction yields 3 moles of lithium hydroxide LiOH How many grams of lithium hydroxide are present?

To determine the grams of lithium hydroxide present, you need to use its molar mass. The molar mass of LiOH is approximately 23.95 g/mol. Therefore, 3 moles of LiOH would be: 3 moles x 23.95 g/mol = 71.85 grams of lithium hydroxide.


How many moles of lithium hydroxide are required to react with 20 mol of CO2?

The balanced chemical equation for the reaction of lithium hydroxide with carbon dioxide is 2 LiOH + CO2 -> Li2CO3 + H2O. The mole ratio of LiOH to CO2 is 2:1, meaning that 40 moles of LiOH are required to react with 20 moles of CO2.


How many moles of water are formed when 15 mL of 0.40 M LiOH is added to 25 mL of 0.60 M H2SO4?

First, determine the limiting reactant by calculating the number of moles for each reactant (moles = concentration x volume). In this case, LiOH is the limiting reactant since it produces 2 moles of water per 1 mole of LiOH. Therefore, 0.006 moles of LiOH will produce 0.012 moles of water.


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