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How many moles of water are formed when 15 mL of 0.40 M LiOH is added to 25 mL of 0.60 M H2SO4?
Wiki User
∙ 10y ago
The value is o,oo6 moles water.
Wiki User
∙ 10y ago
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How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.
When lithium hydroxide pellets are added to a solution of sulfuric acid what is formed?
When lithium hydroxide pellets are added to a solution of sulfuric acid Lithium Sulfate and water are formed. The balanced equation is 2LiOH + H2SO4 ------> Li2SO4 + 2H2O
What happens when sulfur trioxide reacts with water?
H2SO4 is formed
How many moles of water are formed with 230 moles of H2 and 110 moles of O2?
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
How many moles of H2O are produced when 1 mole of MgOH2 reacts with 1 mole of H2SO4?
Go ahead and write the balanced equation: H2SO4 + 2NaOH --> Na2SO4 +2H2O If you have 1 mole of the reactant H2SO4, it will yield 2 moles of the product water. You can tell by the coefficients.
How many moles of H2SO4 are produced from 13 moles of H2O?
Sulfuric acid is not obtained from water.
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.
When lithium hydroxide pellets are added to a solution of sulfuric acid what is formed?
When lithium hydroxide pellets are added to a solution of sulfuric acid Lithium Sulfate and water are formed. The balanced equation is 2LiOH + H2SO4 ------> Li2SO4 + 2H2O
What happens when sulfur trioxide reacts with water?
H2SO4 is formed
How many moles of water are formed with 230 moles of H2 and 110 moles of O2?
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
How many moles of H2O are produced when 1 mole of MgOH2 reacts with 1 mole of H2SO4?
Go ahead and write the balanced equation: H2SO4 + 2NaOH --> Na2SO4 +2H2O If you have 1 mole of the reactant H2SO4, it will yield 2 moles of the product water. You can tell by the coefficients.
According to the following balanced reaction how many moles of NO are formed from 8.44 moles of NO2 if there is plenty of water present?
Balanced equation. 3NO2 + H2O -> 2HNO3 + NO 8.44 moles NO2 (1 mole NO/3 moles NO2) = 2.81 moles NO formed
How many moles of water form when 5.5 moles of oxygen reacts?
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
A biochemist wishes to dilute 75 ml of an aqueous 3.5 M H2SO4 solution to an aqueous 2 M H2SO4 solution. How much water should be added to the solution?
30 mL water.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
If 5.0 moles of C3H8 react how many molecules of water are formed?
1.2x10^25
Which salt is produced when sulfuric acid and calcium hydroxide react completely?
H2SO4 + Ca(OH)2 --> CaSO4 + 2H2O Balance the equation by putting a 2 in front of H2O. Sulphuric acid added to Calcium Hydroxide will form Calcium Sulphate along with water. This is an example of neutralisation reaction where an acid is added to a base, forming a salt and a by product of water.
