Approx. 516 g at 0 0C.
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The molar mass of LiOH is 23.95 g/mol for lithium, 15.999 g/mol for oxygen, and 1.008 g/mol for hydrogen, totaling 41.943 g/mol for LiOH. This means that for every 41.943 grams of LiOH, 44.01 grams of CO2 can be absorbed. To find out how much CO2 can be absorbed by 580.0 grams of LiOH, you can set up a simple ratio and cross-multiply to get your answer.
First, calculate the number of moles of Ca(OH)2: 25.0 g / molar mass of Ca(OH)2. Then, use the mole ratio from the balanced equation to determine the moles of LiOH produced. Finally, convert the moles of LiOH to grams: moles of LiOH * molar mass of LiOH.
To determine the grams of lithium bromide produced, you need to first calculate the moles of lithium hydroxide using its molar mass. Then, use the mole ratio from the balanced chemical equation to find the moles of lithium bromide produced. Finally, convert the moles of lithium bromide to grams using its molar mass to find the answer.
To determine the grams of lithium hydroxide present, you need to use its molar mass. The molar mass of LiOH is approximately 23.95 g/mol. Therefore, 3 moles of LiOH would be: 3 moles x 23.95 g/mol = 71.85 grams of lithium hydroxide.
First, determine the limiting reactant by calculating the number of moles for each reactant (moles = concentration x volume). In this case, LiOH is the limiting reactant since it produces 2 moles of water per 1 mole of LiOH. Therefore, 0.006 moles of LiOH will produce 0.012 moles of water.
LiOH is made of 3 atoms, one of lithium, one of oxygen, and one of hydrogen.
The answer is 445,6 g carbon dioxide.
There are 5800 grams in 5.8 kg since 1 kg is equal to 1000 grams.
1000 Grams per kilogram, so 5800:1000 = 5.8 Kg.
To find the grams of LiOH in the solution, we need to use the percentage concentration of NaOH to calculate the molarity of the solution first. Then, we can use stoichiometry to convert the moles of NaOH to LiOH since they are in a 1:1 ratio. Finally, we can convert the moles of LiOH to grams using its molar mass.
One gram of lithium hydroxide can absorb around 0.39 grams of carbon dioxide through a chemical reaction, forming lithium carbonate and water.
First, calculate the number of moles of Ca(OH)2: 25.0 g / molar mass of Ca(OH)2. Then, use the mole ratio from the balanced equation to determine the moles of LiOH produced. Finally, convert the moles of LiOH to grams: moles of LiOH * molar mass of LiOH.
5800 ' = 1.09848 mi.
To determine the grams of lithium bromide produced, you need to first calculate the moles of lithium hydroxide using its molar mass. Then, use the mole ratio from the balanced chemical equation to find the moles of lithium bromide produced. Finally, convert the moles of lithium bromide to grams using its molar mass to find the answer.
There are 3 feet in one yard. Therefore, 5800 feet is equal to 5800/3 = 1933.3 recurring (that is, 1933.3333...) yards.
To determine the grams of lithium hydroxide present, you need to use its molar mass. The molar mass of LiOH is approximately 23.95 g/mol. Therefore, 3 moles of LiOH would be: 3 moles x 23.95 g/mol = 71.85 grams of lithium hydroxide.
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The balanced chemical equation for the reaction of lithium hydroxide with carbon dioxide is 2 LiOH + CO2 -> Li2CO3 + H2O. The mole ratio of LiOH to CO2 is 2:1, meaning that 40 moles of LiOH are required to react with 20 moles of CO2.