To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
From the law of conservation of mass: 58.5 - 23 = 35.5 grams of chlorine required. Interestingly, 23 and 35.5 are approximations to the gram atomic masses of sodium and chlorine respectively.
Sodium reacts with chlorine to form sodium chloride which is an ionic compound. It has a crystalline structure and has no molecules.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
42
75 g sodium chloride contain 29,75 g sodium.
70
Sodium chloride (NaCl) contain two atoms: 1 sodium and 1 chlorine.
Sodium chloride (NaCl) formula unit has one chlorine atom.
It depends on the concentration of sodium chloride.
From the law of conservation of mass: 58.5 - 23 = 35.5 grams of chlorine required. Interestingly, 23 and 35.5 are approximations to the gram atomic masses of sodium and chlorine respectively.
23.3772 grams are there in four tenths moles of sodium chloride
Sodium reacts with chlorine to form sodium chloride which is an ionic compound. It has a crystalline structure and has no molecules.
There are two elements that make up sodium chloride. They are sodium and chlorine.
Two: sodium and chlorine.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed