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75 g sodium chloride contain 29,75 g sodium.

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9y ago
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John Merlino

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1y ago

If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?

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Q: If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?
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How much table salt is produced when you combine sodium with 1.5 grams of chlorine gas?

2.472686481


What is the number of moles of H2 produced when 23 grams of sodium reacts with water?

The answer is o,5 mol.


How many grams of Chlorine are in 7 grams of Sodium Chloride?

To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.


There is 46 grams of sodium and 23 grams of Chlorine How many gram of sodium chloride can be produced?

Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams


What mass of chlorine gas will react with 92 grams of sodium?

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How many grams of chlorine gas are needed to make 117 grams of sodium chloride?

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What mass of sodium chloride is formed if 22.99 grams of sodium combines with 35.54 grams of chlorine?

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What mass of sodium chloride is produced if 92.0 g of sodium reacts with excess chlorine?

Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).


How many grams of carbon tetrachloride can be produced from reacting 709.0 grams of chlorine with excess methane?

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In a chemical reaction 4 grams of sodium must combine with how many grams of chlorine to produce 10 grams of table salt?

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In a reaction between sodium and chlorine 10 grams of sodium is needed to prepare 35 grams of sodium chloride How many grams of chlorine is needed for this reaction?

Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed


When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?

The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.