The answer is o,5 mol.
dose 23 grams of sodium and 238 grams of uranium have equal number of atoms in them
8.20g of carbon monoxide, how many grams of methanol will be produced?
The equation for the reaction is 4 Na + O2 -> 2 Na2O. This shows that, for complete reaction, one mole of oxygen is required for each four gram atomic masses of sodium. The gram atomic mass of sodium is 22.9898; therefore, 46 grams of sodium constitutes 2.00 moles of sodium, to more than the justified number of significant digits. The gram molecular mass of diatomic oxygen is 31.9988; therefore 160 grams of oxygen constitutes 5.000 moles of diatomic oxygen, to more than the justified number of significant digits. This is well over the minimum amount of oxygen required for complete reaction of all the sodium present. Each two gram atomic masses of sodium produces one gram formula mass of sodium oxide; therefore, the number of gram formula masses of sodium oxide produced is 1.00, to at least the justified number of significant digits.
A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.
5a+10b = 10ab
75 g sodium chloride contain 29,75 g sodium.
155.2 g
The gram atomic mass of sodium is 22.9898, the formula of the least hydrated form of sodium phosphate is Na3PO4.10 H2O, and the gram formula unit mass of this sodium phosphate is 344.09. Therefore, the mass fraction of sodium in this sodium phosphate is 3(22.9898)/344.09 or about 0.20044, and the grams of sodium in 7.2 grams of this sodium phosphate is 1.44 grams of sodium, to the justified number of significant digits.
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
180g I2
dose 23 grams of sodium and 238 grams of uranium have equal number of atoms in them
2.472686481
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
8.20g of carbon monoxide, how many grams of methanol will be produced?
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.