246 g
In one mole of CaCl2, there are 71.08 g of Cl and 40.078 g of Ca.So the entire mole is 111.158 g. In 535 g, you have 4.81297 mole of CaCl2. So you have 9.62594 mole of Cl2. Now with the molar mass of Cl, you can easily find the amount in grams.
There is no such thing as CaCl.
Presumably you mean calcium chloride, which is CaCl2. (Sorry, subscript isn't working)
r.a.m. of calcium is 40
r.a.m. of chlorine is 35.5
Therefore 1 mole of calcium chloride is (1*40) + (2*35.5) = 111 g.
This contains 71g of chlorine.
So 71 / 111 of any mass of calcium chloride is composed of chlorine,
and in 385g there must be (71 / 111) * 385 g = 246 g
CaCl2
Molar mass 111;
so 111 g CaCl2 contains 71 g Chlorine
so 155 g CaCl2 contains (71/111)*155= 99.144 g Chlorine atoms
365 grams of CaCl2 contain 232,27 g chlorine.
About 188.2 grams of Cl.
it's 63.89% Cl. that % of 115g is 73.47g
178g
CaCl would be polar ionic.
Yes, CaCl2 is an ionic compound. It is composed of calcium ions (Ca2+) and chloride ions (Cl-), which are held together by ionic bonds.
Calcium chloride is soluble in water. It ionizes into calcium ions (Ca2+) and chloride ions (Cl-) in solution.
Since 1 centiliter (cl) is equal to 1 gram for water and other similar liquids, 8 centiliters would be equal to 8 grams.
64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.
There are many many chemicals that have CL in them. NaCl - Table salt. CaCl - Calcium Chloride Hydrochloric acid These are a few.
Calcium forms ionic compounds by giving away two electrons to achieve a stable electron configuration. In the case of calcium chloride (CaCl2), each calcium atom gives away two electrons to two chlorine atoms, resulting in a compound with a 1:2 ratio of calcium to chlorine atoms. If it were calcium dichloride, it would imply a 1:1 ratio, which is not the case in this compound.
Calcium chloride is soluble in water. It ionizes into calcium ions (Ca2+) and chloride ions (Cl-) in solution.
Since 1 centiliter (cl) is equal to 1 gram for water and other similar liquids, 8 centiliters would be equal to 8 grams.
CaCl would be polar ionic.
15cL equals 0.15L* There are 100cL per liter
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
Balanced equation. 2K + Cl2 >> 2KCl 39 grams K (1mol K/39.10g )(1mol Cl/2mol K )(35.45g/1 mol Cl ) = 17.7 grams
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
SrCl2 Strontium (Sr) = 87.62 grams/mol 2 Chlorine (Cl) = 70.9 grams/mol ----------------------------------------------------add Strontium chloride = 158.52 grams/mol ============================
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.