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The reaction equation is 8 F2 + 2 NH3 equals N2F4 + 6 HF2. So every mole of NH3 requires four moles of F2. This means 14 moles of F2 or 532 grams.
The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.
1 mole F2 = 37.996g F2 = 6.022 x 1023 molecules F2 85g F2 x 6.022 x 1023 molecules F2/37.996g F2 = 1.3 x 1024 molecules F2
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
Zn= 65.4 F2= 19 x 2= 38 38+ 65.4= 103.4 molar mass of of znf2 is 103.4 grams
first, you need to have a balanced equation. this is S8 + 24F2 = 8SF6 start with your given, which is 17.8g of sulfur 17.8g S8 x 1 mol S8/256.56g S8 (the 256.56 is the molar mass of S8) this gives you .06938. multiply that by 24 mols F2/1 mol S8. which is 1.67 mols of F2. 1.67 mols F2 x 38.00g F2/1 mol F2. (38.00g F2 is the molar mass of F2) your answer is 63.2 g F2 :D
445 g
2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
The reaction equation is 8 F2 + 2 NH3 equals N2F4 + 6 HF2. So every mole of NH3 requires four moles of F2. This means 14 moles of F2 or 532 grams.
The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.
2.
182.88
1 mole F2 = 37.996g F2 = 6.022 x 1023 molecules F2 85g F2 x 6.022 x 1023 molecules F2/37.996g F2 = 1.3 x 1024 molecules F2
F2 means that there are two flourines usually a gas is a diatomic molecule. Since a fluorine molecule has an atomic mass of 18.998 that molar mass of F2 would be 18.9998 *2 = 37.996 except in molar mass the units change so instead of being g/mol it would just be grams. so 37.996 grams
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F2+ most stable>f2>f2-
The answer is two moles of F atoms or 1 mole of F2 molecules.