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4 FeCr2O7 + 8 K2CO3 + O2 ---> 2 Fe2O3 + 8 K2CrO4 + 8 CO2

11moles

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9y ago
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Marriiano

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3y ago
wrong bidawg
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Wiki User

10y ago

I'm assuming you're referring to the well-known oxidation-reduction reaction that produces pure iron and carbon dioxide from iron(III) oxide and carbon monoxide. The balanced equation for that reaction is:

Fe2O3 + 3CO --> 2Fe + 3CO2

Additionally, I'm assuming that you mean how many grams of CO2 are produced, since CO is a reactant, not a product. So, based on that, here's how you proceed:

You're given 48g of iron(III) oxide, so get your molar mass of that reactant, which is 56x2+16x3=160g/mol. You have 48g, so 48/160=0.3mol. The molar ratio of this reactant to carbon dioxide product is 1:3, so take that 0.3 and triple it, so you will yield 0.9mol CO2. Molar mass of carbon dioxide is 44g/mol, and 0.9x44=39.6g, which is the mass of CO2 produced.

Since carbon dioxide is a gas, it might be more practical to give a volume produced instead, and assuming standard conditions, the volume would be 0.9 moles x 22.4 liters/mole = 20.16L. Yay stoichiometry!

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Kayla Bilan

Lvl 2
2y ago

22

Explanation: 44Co2 (4FeCr2O7/8CO2)

Multiply 44 by 4=176 divide by 8 22 moles of FeCr2O7

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Grace Brekke

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2y ago
Oh ok
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Kyleigh Jacobs

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2y ago
So grateful

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12y ago

136 grams

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12y ago

136 grams

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Anonymous

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4y ago

0.249

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Anonymous

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3y ago

11

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Q: How many g of CO is produced from 48 g of Fe2O3?
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How many moles of iron can be produced from the reaction of 10 mol Fe2O3 and 25 mol of CO?

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How many grams of CO react with .390 kg of Fe2O3?

Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.


If 1.00 kg of Fe2O3 completely reacts with CO the volume of CO2 released at STP will be?

There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters


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An alternative method for preparing pure iron from fe2o3 is by reaction with carbon monoxide fe2o3 plus co fe plus CO2 unbalanced a balance the equation use the lowest possible coefficients?

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What is the balanced equation of iron 3 oxide and carbon?

Fe2O3 (s) + 3CO (g) -----> 2Fe (s) + 3CO2 (g) This is just the balanced chemical equation. It says nothing about the actual method and reaction conditions for performing the reaction. The mixture would most likely need to be heated signficantly. Why worry about dealing with carbon monoxide, when simple carbon will do? Again, significant heating of the mixture is required. 2Fe2O3 (s) + 3C (s) -----> 4Fe (s) + 3CO2 (g)


If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?

mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==


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CO will react with 1.75 moles of Fe2O3?

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