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How many grams of oxygen are required to burn 100 gram of propane?
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many grams of oxygen will be in 2 moles of pottassium dichromate?
The answer is 224,141 grams oxygen.
How many grams of Oxygen is in 6 O2?
There are 192 grams of oxygen in 6 moles of O2.
How many moles of in 320 grams of oxygen?
320 grams of oxygen is the equivalent of 10 moles.
How many grams of oxygen are in 477 grams of water?
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
How many moles of oxygen are contained in 2.43 grams of oxygen?
1 mol of oxygen is 16.00g. Therefore 2.43g of oxygen would contain 0.152 mols of oxygen. (2.43g/16.00g)
How many moles are there in 12.8grammes of oxygen?
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
How many oxygen atoms are there in 3.45 grams of H2O?
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
How many grams are contained in 0.644 mol oxygen?
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form.. How many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
