1,9 grams
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
16 grams of oxygen how many moles is 0,5 moles.
The answer is 224,141 grams oxygen.
There are 192 grams of oxygen in 6 moles of O2.
320 grams of oxygen is the equivalent of 10 moles.
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
1 mol of oxygen is 16.00g. Therefore 2.43g of oxygen would contain 0.152 mols of oxygen. (2.43g/16.00g)
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.