Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
4NH3 + 5O2 ==> 4NO + 6H2O balanced equation for the reaction4.5 moles NH3/4 = 1.125
3.2 moles O2/5 = 0.64 THIS IS THE LIMITING REACTANT
moles of H2O formed = 3.2 moles O2 x 6 moles H2O/5 moles O2 = 3.84 moles H2O formed
42.5 g of NH3 is equivalent to around 2.5 moles. Since there are 3 moles of H2O produced for every 2 moles of NH3 used, 3.75 moles of H2O are produced. This around 3.79 g of water.
According to this balanced equation:Na2O + H2O --> 2NaOH42 moles Na2O react with 42 moles H2O
How many moles of C are needed to react with 0.490 mole SO2?
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
4.67
12 moles Li
3
1.2x10^25
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
According to this balanced equation:Na2O + H2O --> 2NaOH42 moles Na2O react with 42 moles H2O
When 3 moles Cu react 3 moles of copper nitrate are obtained.
How many moles of C are needed to react with 0.490 mole SO2?
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
4.67
12