How many grams of H2 are needed to produce 13.14g of NH3?

Answer 1

The balanced equation for the formation of NH3 is N2 + 3 H2 --> 2 NH3. 13.64 grams of ammonia is equal to .801 moles. Then 1.2015 moles of hydrogen are needed, or 2.42 grams.

Answer 2

3H2 + N2 -->2NH3 6g of H2 give 34g of NH3. 2.1247g of H2 give 12.04g of NH3.

Answer 3

3H2 + N2 --> 2NH3 is the balanced equation. 13.14g of ammonia is 0.773mol, and that means 1.16mol hydrogen (according to the 2:3 ratio.) 1.16mol of hydrogen = 2.32g of hydrogen.

Answer 4

(6/34)*13.7

=2.4176 grams of H2

Answer 5

The answer is 1,97 h hydrogen.

Answer 6

1,364 g hydrogen are needed.

Answer 7

2.0851gH2