The balanced equation for the formation of NH3 is N2 + 3 H2 --> 2 NH3. 13.64 grams of ammonia is equal to .801 moles. Then 1.2015 moles of hydrogen are needed, or 2.42 grams.
3H2 + N2 -->2NH3 6g of H2 give 34g of NH3. 2.1247g of H2 give 12.04g of NH3.
3H2 + N2 --> 2NH3 is the balanced equation. 13.14g of ammonia is 0.773mol, and that means 1.16mol hydrogen (according to the 2:3 ratio.) 1.16mol of hydrogen = 2.32g of hydrogen.
(6/34)*13.7
=2.4176 grams of H2
The answer is 1,97 h hydrogen.
1,364 g hydrogen are needed.
2.0851gH2
769.0 grams
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
8 grams is 1 Kasu
There are 200 grams in 200 grams.
How many grams are in an ounce
10.1 grams
319g Cl2 are needed.
A lot
800 g oxygen are needed.
mass of CaCO3 = 246 grams
201
326g
530,3 g potassium iodide are needed.
The needed mass of sodium is 91,659 g (for 2 moles H2).
You need 150,41 g oxygen.
Answering "http://wiki.answers.com/Q/How_many_grams_of_calcium_chloride_are_needed_to_produce_10_g_of_potassium_chloride"
112,64 g of NaOH and 138,1 g of H2SO4