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molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
The gram molecular mass of carbon tetrachloride is 12.011 + 4(35.453) or 153.823. Each mole contains Avogadro's Number of molecules. Therefore, the number of molecules in 200 grams is (200/153.823) X Avogadro's Number or 7.83 X 1023 molecules, to the justified number of significant digits.
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The number of molecules in 15 g ethane is approx. 3,011.10e23.
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
301.8g H2O
How many molecules are in 94 grams of sodium fluoride
The gram molecular mass of carbon dioxide is about 44.01 grams. By definition, this value is the number of grams of carbon dioxide that contains Avogadro's Number ("AN") of molecules. Avogadro's Number is about 6.022 X 10^23. Therefore the number of molecules in 1 gram is (1/44.01)(AN) or 2 X 10^21 molecules, to the justified number of significant digits.
The gram molecular mass of carbon tetrachloride is 12.011 + 4(35.453) or 153.823. Each mole contains Avogadro's Number of molecules. Therefore, the number of molecules in 200 grams is (200/153.823) X Avogadro's Number or 7.83 X 1023 molecules, to the justified number of significant digits.
9.03 × 1023
The density of O2 is 31.9988 grams per mole, meaning there are 0.143 grams and 4.47 mmols present. The density of NH3 is 17.0305 grams per mole, giving 4.09 mmols of ammonia. This means that they have approximately the same number of mmoles, thus the same number of molecules.
A mole of a substance contain 6,022 140 857.10ex23 (number of Avogadro - NA ) molecules.A mass (in grams) contain a number of molecules equal to:(given mass x number of Avogadro)/molar mass
The number of molecules in 15 g ethane is approx. 3,011.10e23.
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The answer is: approx. 10e23 molecules.