The molar mass of sodium chloride is 58.5 g/mole. Thus You would have to dissolve 25 * 58.5 g/l to obtain a 25 M NaCl-solution.
The 1462,5 g/l are far beyond the solubility limit of 360 g/l for sodium chloride in water which means that under standard conditions such a solution is not possible. After saturating the solution with 360 g/l of NaCl there would still be 1102,5 g/l of crystalline NaCl left.
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Assuming each 500ml bottle of water weighs around 500 grams (since 1 ml of water is approximately 1 gram), the total weight of 40 bottles would be approximately 20,000 grams or 20 kilograms.
At 70 degrees Celsius, approximately 38 grams of potassium chloride (KCl) can dissolve in 100 grams of water. Therefore, in 200 grams of water, about 76 grams of KCl would dissolve. Keep in mind that solubility can vary slightly based on specific conditions.
The solubility of potassium chloride in water is approximately 34 grams per 100 grams of water at room temperature. Therefore, in 200 grams of water, the maximum amount of potassium chloride that can dissolve would be around 68 grams.
Approximately 30.4 grams of potassium chloride would dissolve in 100 cm3 of water at room temperature.
At 10 degrees Celsius, potassium chloride (KCl) has a solubility of approximately 30 grams per 100 grams of water. To dissolve 350 grams of KCl, you would need about 1,166.67 grams of water, calculated by taking the ratio of the solubility: ( 350 , \text{g KCl} \times \frac{100 , \text{g water}}{30 , \text{g KCl}} ). Thus, around 1,167 grams of water are required to fully dissolve 350 grams of KCl at that temperature.
Solubility increases with temperature, but the solubility of sodium chloride in water is 316 grams per litre at 0 degrees Celsius, and 330 grams per litre at 70 degrees Celsius. Since room temperature is somewhere between these two, this gives upper and lower limits of the solubility at room temperature. 50 grams of water has a volume of 50 cubic centimetres, or 0.05 litres. In one litre you could dissolve between 316 grams and 330 grams, so in 0.05 litres you could dissolve between 15.8 and 16.5 grams, where 15.8 = 316 x 0.05 and 16.5 = 330 x 0.05. So we can say it's around 16 grams of NaCl in 50 grams of water at room temperature.
The solubility of barium carbonate (BaCO3) in water is very low, approximately 0.0002 grams per 100 mL at room temperature. Therefore, in 1000 mL of water, about 0.002 grams of BaCO3 would dissolve. This indicates that BaCO3 is not soluble in water and will mostly remain undissolved.
The minimum amount of water required to dissolve 5 grams of magnesium sulfate would be approximately 72 mL at room temperature (25°C).
To make a liter of water, you would need two 500ml bottles of water. This is because 1 liter is equivalent to 1000ml. Therefore, two 500ml bottles combined would give you a total of 1000ml or 1 liter of water.
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, you would need to know the solubility of 1-pentanol in water at a specific temperature. Once you have that information, you can calculate the total mass of 1-pentanol that will dissolve by adding the mass of the water to the mass of the 1-pentanol that can dissolve in it to form a saturated solution.
To determine the mass of NH4Cl needed to create a saturated solution in 200 grams of water at 50°C, we first need to consult the solubility data for NH4Cl at that temperature, which is approximately 37.2 grams per 100 grams of water. Thus, for 200 grams of water, the solubility would be about 74.4 grams of NH4Cl (37.2 g x 2). Therefore, you would need to dissolve approximately 74.4 grams of NH4Cl to achieve saturation at that temperature.