The molar mass of sodium chloride is 58.5 g/mole. Thus You would have to dissolve 25 * 58.5 g/l to obtain a 25 M NaCl-solution.
The 1462,5 g/l are far beyond the solubility limit of 360 g/l for sodium chloride in water which means that under standard conditions such a solution is not possible. After saturating the solution with 360 g/l of NaCl there would still be 1102,5 g/l of crystalline NaCl left.
Dissolve 14,61 g NaCl reagent grade in 1 L demineralized water at 20 0C.
You need 12,5 sodium chloride.
The value is 1,461 g.
Take 37.25g of KCl exactly and dissolve in 500ml of water
Every 100 grams (100 millilitres) of boiling water (even hard water) will dissolve a maximum of about 40 grams of salt, so anything in excess of that amount just will not dissolve. If your poured a teaspoon of salt grains into a pan of boiling water it would dissolve immediately - almost no time at all.
using water displacement because it doesnt float on water and it doesnt dissolve in water
what are the volume of piece of chalk
26.8125 g
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
2
Whether all of the sugar dissolved or not, and it would be very unlikely that it would all dissolve in that small an amount of water, the total mass of the solution or mixture would be 250 grams.
A non polar compound would be least likely to dissolve in water.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
Solubility increases with temperature, but the solubility of sodium chloride in water is 316 grams per litre at 0 degrees Celsius, and 330 grams per litre at 70 degrees Celsius. Since room temperature is somewhere between these two, this gives upper and lower limits of the solubility at room temperature. 50 grams of water has a volume of 50 cubic centimetres, or 0.05 litres. In one litre you could dissolve between 316 grams and 330 grams, so in 0.05 litres you could dissolve between 15.8 and 16.5 grams, where 15.8 = 316 x 0.05 and 16.5 = 330 x 0.05. So we can say it's around 16 grams of NaCl in 50 grams of water at room temperature.
Depends on how accurate you need to be. Ideally 56.11g of KOH made up to 1L. Dissolve 56.11g in say 500ml then make up to 1l using water - 1l volumetric is the way to go. If you need 1000L then I would suggest 56.11kg chucked into 1000L All the best