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5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 )
= 0.0306 moles Ba(OH)2
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What is the mass of 2.75 moles of sodium hydroxide?
Molar mass of NaOH is 39.998 grams. So, 2.75 mol NaOH (39.998g NaOH/1 mol NaOH) = 109.9945 grams NaOH ( you do the sigi figi )
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
How many moles of NaOH are needed to prepare 2.00 L of a .250 M NaOH solution?
Molarity equals mole per liter M = mol/L So solve for moles by multiplying liters to the other side of the equation and you get: mol=ML Plug in your numbers mol=0.250M*2.00L mol=0.5 or 19,99855 grams = aprox. 20 grams
20 grams of NaOH to moles?
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
How many mole of atoms are contained in 25.0 g naoh?
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
What is the mass of 2.75 moles of sodium hydroxide?
Molar mass of NaOH is 39.998 grams. So, 2.75 mol NaOH (39.998g NaOH/1 mol NaOH) = 109.9945 grams NaOH ( you do the sigi figi )
How many grams of sodium hydroxide (NaOH) are there in 0.150 mol?
0,15 moles NaOH contain 6 g.
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
How many moles of sodium hydroxide are required to neutralize 0.20 mol of nitric acid?
Balanced Equation. NaOH + HNO3 >> NaNO3 + H2O Now, Molarity = moles of solute/liters of solution 0.800M HNO3 + mol/2.50L mol of HNO3 = 2 2mol HNO3 (1mol NaOH/1molHNO3 )(39.998g NaOH/1mol NaOH ) = 79.996 grams
What is the weight of 1 liter of 5 Molar sodium hydroxide?
5 M NaOH = 5 mol/L NaOH. 1 mol of NaOH = 40 g NaOH. You can get the number of grams by multiplying 5 mol/L and 40g/mol. This will give you 200g/L. Just multiply by the volume, which is 1 Liter, and you will get 200 g of NaOH.
How many moles of NaOH are needed to prepare 2.00 L of a .250 M NaOH solution?
Molarity equals mole per liter M = mol/L So solve for moles by multiplying liters to the other side of the equation and you get: mol=ML Plug in your numbers mol=0.250M*2.00L mol=0.5 or 19,99855 grams = aprox. 20 grams
If 1.20 grams of sodium metal are reacted with 3.00 ml of water how many grams of NaOH will be produced?
First write balance equation 2Na + 2H2O --> 2NaOH + H2 molar mass Na = 22.99 g/mol molar mass H2O = 18.02 g/mol molar mass NaOH = 40.0 g/mol Determine limiting reagent. 1.20 g Na * 1mol Na/22.99g Na = 0.05219 (0.0522) mol Na Since 2Na = 2NaOH in balanced equation, The mol of NaOH is also 0.0522 3ml h20 = 3 gram h20 (1ml^3=1g^3) 3g H20 * 1mol/18gH20 = 0.167 (0.17) mol H20 So .17 ml H20 equals .17 mol NaOH and .0522 mole Na equals .0522 mol NaOH The smaller one is the limiting reagent, which in this case is Na 0.0522mol NaOH*40g NaOH/1mol NaOH = 2.09 gram NaOH
20 grams of NaOH to moles?
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
How many mole of atoms are contained in 25.0 g naoh?
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
What mass of NaOH is required to make up 100 mL of a 0.5000 M solution?
Two parts.Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters )0.5000 M NaOH = X moles/0.1 L= 0.05 moles NaOH--------------------------------now,0.05 moles NaOH (39.998 grams/1 mole NaOH)= 1.99 grams NaOH required====================( could call it 2.00 grams )
How many grams of Ca-OH-2 are needed to prepare 100 mL of solution of 0.1 M Ca-OH-2?
M = moles/liter 100 ml = 0.1 liter so 0.01 mole NaOH / 0.1 liter = .1 M NaOH you can find how many grams of NaOH in .01 moles by multiplying .01 by the atomic weight of a mole of NaOH, which you can find by adding up the atomic weight of Na, and O, and H.
