Call the unknown mass m. Then, from the problem statement, m/(400 + m) = 12.5 % = 0.125. Applying standard algebra techniques, multiply both sides of this equation by (400 + m) to result in m = 0.125(400 + m); m(1 - 0.125) = 400 X 0.125; 0.875m = 50; m = 57.1 grams, to the justified number of significant digits.
The products of the reaction are solid calcium sulfate and aqueous lithium nitrate.
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
If the silver nitrate and ammonium chloride are both in solution when mixed, the very sparingly soluble silver chloride precipitates as a solid, leaving ammonium nitrate in the solution.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
A yellow precipitate of silver iodide (AgI).
The products of the reaction are solid calcium sulfate and aqueous lithium nitrate.
Lead nitrate + potassium sulfate ---> Lead sulfate + Potassium nitrate
When a cooled saturated potassium nitrate solution is added to water, the concentration of the potassium nitrate decreases making it less likely that he substance will precipitate out of solution.
When zinc nitrate solution is added to lead nitrate solution you willÊapparently observe a black solid being formed. All of the research yielded facts from adding solid metal to either zinc or lead.
Calcium nitrate and magnesium will not react since calcium is more reactive than magnesium and so, magnesium does not displace calcium (See Reactivity Series). However, if Calcium nitrate is in aqueous solution (dissolved in water), some bubbles may be seen when Magnesium is added to it, since the Magnesium would be reacting with the water and producing hydrogen bubbles.
Any reaction occur.
it doesn't
Silver nitrate will dissolve in distilled water. When added to a salt solution silver chloride will fall out of solution.
Nothing. They do not react.
Sh!t happens.
None
The solution turns purple.